double.TryParse() ignores dots in my string

Question

So I'm currently using the following code to parse a string into a double:

double.TryParse(resultLabel.Content.ToString(), out newNumber);

The parsing is executed but it ignores the . in the code. For Example:

3.3 gets parsed to 33
6.7 gets parsed to 67
9.5 gets parsed to 95

Does anyone know why is that and how to fix it?

Thanks in advance!

I tried to track it down with break points where it it parses falsely and it was immediately after this line.

What locale are you in? What happens if you try to parse `3,3`, `6,7` or `9,5`? Take a look at: https://learn.microsoft.com/en-us/dotnet/api/system.double.tostring?view=net-6.0 — Flydog57, Sep 09 '22 at 15:45
In you current culture `.` (dot) is a hroup separator which is ignored, while `,` (comma) is decimal one. — Dmitry Bychenko, Sep 09 '22 at 15:50

score 1 · Accepted Answer · answered Sep 09 '22 at 15:57

You need to pass culture that use "." as decimal separator (e.g. InvariantCulture)

var resultLabel = "3.3";
var success = double.TryParse(resultLabel, out var newNumber); //success is false
success = double.TryParse(resultLabel, NumberStyles.Any, CultureInfo.InvariantCulture, out newNumber); //success is true

double.TryParse() ignores dots in my string

1 Answers1