Boolean "True" is not printing from set in Python

Question

c= {1,3,5,89.07, True, "Night", 1,3}
print(c)

when I run this code, the output I received was, {1, 3, 'Night', 5, 89.07}

but when I replaced the "True" bool with False, the output was, {False,1, 3, 'Night', 5, 89.07}

So, why it is not giving "True" bool in first case ?

`print({ 1, True })` outputs `{1}` and `print({ 0, False })` outputs `0`. Strange. — Quelklef, Sep 12 '22 at 06:29
but for dictionaries we use ":" to specify the keys and values. Here the scenario is different. Its really strange. — Bhushan Patil, Sep 12 '22 at 06:34

score 1 · Answer 1 · answered Sep 12 '22 at 06:31

1

Note that a similar effect is observed for 0:

>>> print({ 1, True })
{1}
>>> print({ 0, False })
{0}

This seems to be because in Python bool is a subclass of int, and often False acts like 0 and True like 1:

>>> isinstance(True, int)
True
>>> False + True
1
>>> False * 100
0
>>> 8 ** False
1

It's even the case that False == 0 and True == 1!

So in your case because 1 is already in your set, adding True to it makes no difference. But if you add False you get a new element.

answered Sep 12 '22 at 06:31

Quelklef

Yeah, now I got it. Thank you Quelklef. It was really helpful. – Bhushan Patil Sep 12 '22 at 06:39
If you find that this answer solved your question. Please mark it as solved, there is a check mark next to the answer. @Quelklef nice explanation. – programandoconro Sep 12 '22 at 06:45

1 Answers1