Run code without transaction in transactional mehod spring

Question

I have service like this:

class ServiceImpl implements Service {
   @Override
   @Transactional
   public int method() {
      //some logic in transaction
      method2();//I want run this without transaction
      return 2;
   }

   @Override
   @Transactional(propagation = Propagation.REQUIRES_NEW)
   public void method2() {
     //external api call
   }
}

How can I run method2 without transaction or in new transaction? Can I run in my controller class this 2 method like this:

service.method();
service.method2();

@ShrikarKalagi in first transaction i save data to database, and i need it to be save as soon as possiible, in the second transaction i call rest api to other client — grap, Sep 23 '22 at 11:34

score 2 · Accepted Answer · answered Sep 23 '22 at 09:38

2

@Transactional is powered by Aspect-Oriented Programming. Therefore, processing occurs when a bean is called from another bean. You can resolve this problem by

self-inject

class ServiceImpl implements Service {

   @Lazy private final Service self;
   @Override
   @Transactional
   public int method() {
      //some logic in transaction
      self.method2();//I want run this without transaction
      return 2;
   }

   @Override
   @Transactional(propagation = Propagation.REQUIRES_NEW)
   public void method2() {
     //external api call
   }
}

create another bean.

class ServiceImpl implements Service {

   private final ExternalService service;
   @Override
   @Transactional
   public int method() {
      //some logic in transaction
      method2();//I want run this without transaction
      return 2;
   }

   @Override
   public void method2() {
     service.method2();
   }
}

@Service
class ExternalService{

   @Transactional(propagation = Propagation.REQUIRES_NEW)
   public void method2() {
     //external api call
   }
}

answered Sep 23 '22 at 09:38

viking

260
2
10

What if I call in controller method my transactional methods like this: service.method(); service.method2(); It will be One transaction? or two ? – grap Sep 23 '22 at 11:03
two different transaction – viking Sep 23 '22 at 11:16
So it could be also a solution? Since I have two proxies? – grap Sep 23 '22 at 11:27
Now I don't know what do you want to achieve. When you called `service.method()` invoked the method `method` will have a separate transaction. If you called `service.method2` also same situation – viking Sep 23 '22 at 11:44
But if I will invoke in method(){method2()} it will be one transaction? – grap Sep 23 '22 at 11:55
No, will be two, but you asked `How can I run method2 without transaction or in new transaction` so if you want disable transaction from method2 change propagation to NOT_SUPPORTED. You cannot achieve one transaction when both method are using separeted transactions by propagation REQUIRED and REQUIRES_NEW. – viking Sep 23 '22 at 12:24
when I call method2() in method() I have sonar issue on method2() : "@Transactional requirement is incompatible with the one for this method." It is okey ? in method2() i set @Transactional(propagation = Propagation.NOT_SUPPORTED) – grap Sep 23 '22 at 12:50
Try to organize your code by using another bean to manage transactions – viking Sep 23 '22 at 15:29

Run code without transaction in transactional mehod spring

1 Answers1