C++ not implicitly casting in friend function operator?

Question

How does C++ go about implicitly casting when it comes to friend function?

This is my friend function implementation :

bool operator==(Point& x, Point& y) {
    return x.x == y.x;
}

In my class I have a simple converstion constructor :

Point(int x=5) : x(x){}

Why does the following code not implicitly convert int into my class Point ?

cout << (p == 5) << endl;
cout << (5 == p) << endl;