#!/usr/bin/env python3
import argparse
parser = argparse.ArgumentParser()
parser.add_argument('--selection', '-s')
parser.add_argument('--choice', '-c', default = argparse.SUPPRESS)
args = parser.parse_args()
def main(selection, choice):
print(selection)
print(choice)
if __name__=='__main__':
main(args.selection, args.choice)
The example provided is just to provide something simple and short that accurately articulates the actual problem I am facing in my project. My goal is to be able to ignore an argument within the code body when it is NOT typed into the terminal. I would like to be able to do this through passing the argument as a parameter for a function. I based my code off of searching 'suppress' in the following link: https://docs.python.org/3/library/argparse.html
When I run the code as is with the terminal input looking like so: python3 stackquestion.py -s cheese
, I receive the following error on the line where the function is called:
AttributeError: 'Namespace' object has no attribute 'choice'
I've tried adding the following parameter into parser like so:
parser = argparse.ArgumentParser(argument_default=argparse.SUPPRESS)
I've also tried the above with
parser.add_argument('--choice', '-c')
But I get the same issue on the same line.
@Barmar answered this question in the comments. Using 'default = None' in parser.add_argument works fine; The code runs without any errors. I selected the anser from @BorrajaX because it's a simple solution to my problem.