i want to get a loop if we accidently input an alphabet

Question

#if we put an alphabet in 'x' it should loop infinite times

x = str(input("put number here: "))

so I wanna loop x statement in python if we put an alphabet in x and I've been at it for the past month but all i'm getting is for loop and those continue loops, I've tried them but they don't work (at least with my brain) so please some help would be appreciated.

Please update your question with one example of code you have tried and a sample input you would supply and the expected output. — quamrana, Sep 24 '22 at 12:08
`input` already returns a string; calling `str` on the returned value doesn't do anything. (IIRC, `str` just returns its argument when it's a `str`, rather than creating a new string: `str` values are immutable, so creating a copy makes no sense.) — chepner, Sep 24 '22 at 12:17
Do the answers to this [question](https://stackoverflow.com/questions/23294658/asking-the-user-for-input-until-they-give-a-valid-response) help at all? — quamrana, Sep 24 '22 at 12:20

score 0 · Answer 1 · answered Sep 24 '22 at 12:40

0

I'm not sure I've got you right
but maybe you're looking for something like this:

while variable := input("put number here: "):
    if not variable.isalpha():
        break

this code places user's input inside variable and do it only if input is not [a-zA-Z]

answered Sep 24 '22 at 12:40

Dmitriy Neledva

867
4
10

can make it so that it loops even if I type in "asd54" ? – Dhruva Choudhary Sep 24 '22 at 14:10
if your variable should be `int` only `if not variable.isalpha():` is to be changed to `if variable.isnumeric():` – Dmitriy Neledva Sep 24 '22 at 17:52
@Dhruva if variable should be alphanumeric like `asd54` then this line `if not variable.isalpha():` is what you need – Dmitriy Neledva Sep 24 '22 at 17:53

i want to get a loop if we accidently input an alphabet

1 Answers1