#include <iostream>;
using namespace std;
int main()
{
int a, b;
cout << "please inter number \n";
cin >> a ;
cout << "please inter number \n";
cin >> b ;
cout << "********\n" ;
float pi = 3.14 ;
float area = (pi*b*b/4) * ((2*a-b) / (2*a+b));
cout << area << endl;
return 0;
}
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463035818_is_not_an_ai
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Mahammad Qasm
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2what is the input? What is expected output? – 463035818_is_not_an_ai Sep 26 '22 at 19:31
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1`(2*a-b) / (2*a+b)` is using integer arithmetics – 463035818_is_not_an_ai Sep 26 '22 at 19:32
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2why are `a` and `b` not `float` ? – 463035818_is_not_an_ai Sep 26 '22 at 19:32
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@463035818_is_not_a_number make that an answer. – lorro Sep 26 '22 at 19:33
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not a programming problem – Hariom Singh Sep 26 '22 at 19:33
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The input for a and be is a=20, b=10 – Mahammad Qasm Sep 26 '22 at 19:36
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@MahammadQasm -- *The input for a and be is a=20, b=10* -- But `a` and `b` are not `float`. Why did you make them `int`? It also makes more sense to make them `float` anyway, as why should the input not also be fractional, i.e. `2.3` or `5.9`? – PaulMcKenzie Sep 26 '22 at 19:39
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463035818_is_not_a_number. Thanks the problem was using int instead of float in for a & b. – Mahammad Qasm Sep 26 '22 at 19:42