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Example with iOS: I should register an URL scheme or several URL schemes in my app, then tell the third developers to add these URL schemes in their app's white list in Info.plist with key LSApplicationQueriesSchemes, then call openURL:options: by UIApplication instance. Now they succeeded. But I don't know how to return to these apps after something is done in my app! I have no way to add their URL schemes in advance!

The issue in the Android platform is similar with the iOS.

I noticed that other apps are working well in this business.

This is an example: https://youtube.com/shorts/NE1gxwhTnA4?feature=share

西大蛋子儿
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  • Similar question: https://stackoverflow.com/questions/9022967/how-can-i-launch-back-the-app-that-opened-my-custom-url-scheme – Raptor Sep 28 '22 at 09:35
  • You can identify the source application via `UIApplicationLaunchOptionsSourceApplicationKey`. From the received Bundle ID, you can launch the custom URL scheme corresponding to the source application. But this only works for the known URL scheme list that can be found online. – Raptor Sep 28 '22 at 09:38
  • I know, I can ask the third developers to do this. But I can not add these URL schemes in my app's Info.plist with key `LSApplicationQueriesSchemes` when packaging app in advance. – 西大蛋子儿 Sep 28 '22 at 13:58
  • Why can't you update the `Info.plist` with known URL schemes? – Raptor Sep 29 '22 at 02:12
  • They are not known! Because the third developers will launch my app in anytime. Perhaps I need a middle web to do this instead. When I want to return, I open the web through `openURL:options:` by UIApplication instance, and tell it to open the previous app such as `xxxapp://xxx.xxx`. I have to bypass this whitelist restriction. I don't know whether built-in browser in app such as `WKWebView` can do this, otherwise the appreance will be different with the social apps such Wechat and Alipay and so on. It will jump to Safari and then jump back to the previous app. – 西大蛋子儿 Sep 29 '22 at 03:33

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