Return 64 bit integer from purrr::map_*

Question

How do I return a 64-bit integer from purrr::map_*?

Below does not work

library(bit64)
library(tidyverse)

tibble(x=1:3) %>% 
  mutate(y=map_int(x,~{return(as.integer64(2^55))}))

Error in mutate(): ! Problem while computing y = map_int(...). Caused by error: ! Can't coerce element 1 from a double to a integer Run rlang::last_error() to see where the error occurred.

If I use map() instead of map_*() then I get a list-column of integer64. From what I understand, tibble/dplyr supports columns of 64-bit integers, so it would be great to know how to return them from map_*()

just curious, why don't you just use `map()` followed by `%>% unnest(y)`? — langtang, Sep 29 '22 at 21:45
@langtang, that is a great work-around, thank you. I didn't realize unnest worked like that. This solves my problem. — Ben Carlson, Sep 30 '22 at 19:55

score 2 · Accepted Answer · answered Oct 01 '22 at 13:36

2

Probably easiest here is to simply pipe to unnest():

tibble(x=1:3) %>% 
  mutate(y=map(x,~as.integer64(2^4))) %>%
  unnest(y)

Output:

# A tibble: 3 × 2
      x       y
  <int> <int64>
1     1      16
2     2      16
3     3      16

answered Oct 01 '22 at 13:36

langtang

22,248
1
12
27

Return 64 bit integer from purrr::map_*

1 Answers1