how do I store month, day and year in 3 separate variables from the same input? (C++). it needs to be in MM / DD / YYYY with spaces between the /

Question

int month, day, year;
cout << "Enter your date of birth" << endl;
cout << "format: month / day / year  -->" << endl;
cin >> month;
cin >> day;
cin >> year;

it needs to be in MM / DD / YYYY with spaces between the /.

hi, im new to c++ do you mind sharing an example code please? thank you so much. — thunderOP, Sep 30 '22 at 07:35
probably simplest just to read the slashes into a char variable (and probably check that what was read was actually a slash) — Alan Birtles, Sep 30 '22 at 07:44
@i486 Why? The OP decorated this question with the C++ and `cin` tag. — Bob__, Sep 30 '22 at 08:13
@fudo `scanf` works with C++ without any problem. Do you know it? — i486, Sep 30 '22 at 12:28

score 2 · Answer 1 · answered Sep 30 '22 at 07:51

2

As per this answer on a similar question, you can't cin multiple variables in a single shot, but you should be able to chain multiple cin, type in a single input and have each cin get its own value from standard input.

NOT TESTED

int year, month, day;
char slash;

// example input: 2022 / 10 / 12
cin >> year >> slash >> month >> slash >> day;

answered Sep 30 '22 at 07:51

fudo

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1

[Tested](https://godbolt.org/z/TbGcPP6Mr). – Bob__ Sep 30 '22 at 08:21

score 1 · Answer 2 · answered Sep 30 '22 at 07:43

You can use strptime to parse time from input. For example.

struct tm t {0};
std::string input;
std::cin >> input;
if (strptime(input.c_str(), "%m/%d/%Y", &t)){
    int d = t.tm_mday;
    int m = t.tm_mon + 1;
    int y = t.tm_year + 1900;
} else {
    std::cout << "invalid date format\n";
}

how do I store month, day and year in 3 separate variables from the same input? (C++). it needs to be in MM / DD / YYYY with spaces between the /

2 Answers2