Why 2nd console not priniting?

Question



let func=(a,b)=>{
  console.log(a+b)
}

let funci2=func=>(a,b)=>{
  console.log('2nd console')
  func(a+b)
}

let a =3
let b=5

funci2(func(a,b))

Came up with problem while programming. I know it's going to be something very childish. In JS, why 2nd console is not printing? Output is just 8.

Try replacing `console.log(a+b)` by `console.log(a, b)` and you'll see why `a+b` is `NaN` in there. — Bergi, Oct 03 '22 at 20:01

score 0 · Answer 1 · answered Oct 03 '22 at 19:51

0

funci2 takes one parameter and returns an arrow function. You do not call that function, so the console.log statement inside is not executed.

answered Oct 03 '22 at 19:51

Unmitigated

1 Answers1