How to convert a Java object (bean) to key-value pairs (and vice versa)?

Question

Say I have a very simple java object that only has some getXXX and setXXX properties. This object is used only to handle values, basically a record or a type-safe (and performant) map. I often need to covert this object to key value pairs (either strings or type safe) or convert from key value pairs to this object.

Other than reflection or manually writing code to do this conversion, what is the best way to achieve this?

An example might be sending this object over jms, without using the ObjectMessage type (or converting an incoming message to the right kind of object).

Answer 1

Lots of potential solutions, but let's add just one more. Use Jackson (JSON processing lib) to do "json-less" conversion, like:

ObjectMapper m = new ObjectMapper();
Map<String,Object> props = m.convertValue(myBean, Map.class);
MyBean anotherBean = m.convertValue(props, MyBean.class);

(this blog entry has some more examples)

You can basically convert any compatible types: compatible meaning that if you did convert from type to JSON, and from that JSON to result type, entries would match (if configured properly can also just ignore unrecognized ones).

Works well for cases one would expect, including Maps, Lists, arrays, primitives, bean-like POJOs.

Answer 2

There is always apache commons beanutils but of course it uses reflection under the hood

Answer 3

This is a method for converting a Java object to a Map

public static Map<String, Object> ConvertObjectToMap(Object obj) throws 
    IllegalAccessException, 
    IllegalArgumentException, 
    InvocationTargetException {
        Class<?> pomclass = obj.getClass();
        pomclass = obj.getClass();
        Method[] methods = obj.getClass().getMethods();


        Map<String, Object> map = new HashMap<String, Object>();
        for (Method m : methods) {
           if (m.getName().startsWith("get") && !m.getName().startsWith("getClass")) {
              Object value = (Object) m.invoke(obj);
              map.put(m.getName().substring(3), (Object) value);
           }
        }
    return map;
}

This is how to call it

   Test test = new Test()
   Map<String, Object> map = ConvertObjectToMap(test);

Answer 4

Code generation would be the only other way I can think of. Personally, I'd got with a generally reusable reflection solution (unless that part of the code is absolutely performance-critical). Using JMS sounds like overkill (additional dependency, and that's not even what it's meant for). Besides, it probably uses reflection as well under the hood.

Answer 5

Probably late to the party. You can use Jackson and convert it into a Properties object. This is suited for Nested classes and if you want the key in the for a.b.c=value.

JavaPropsMapper mapper = new JavaPropsMapper();
Properties properties = mapper.writeValueAsProperties(sct);
Map<Object, Object> map = properties;

if you want some suffix, then just do

SerializationConfig config = mapper.getSerializationConfig()
                .withRootName("suffix");
mapper.setConfig(config);

need to add this dependency

<dependency>
  <groupId>com.fasterxml.jackson.dataformat</groupId>
  <artifactId>jackson-dataformat-properties</artifactId>
</dependency>

Answer 6

When using Spring, one can also use Spring Integration object-to-map-transformer. It's probably not worth adding Spring as a dependency just for this.

For documentation, search for "Object-to-Map Transformer" on http://docs.spring.io/spring-integration/docs/4.0.4.RELEASE/reference/html/messaging-transformation-chapter.html

Essentially, it traverses the entire object graph reachable from the object given as input, and produces a map from all primitive type/String fields on the objects. It can be configured to output either:

• a flat map: {rootObject.someField=Joe, rootObject.leafObject.someField=Jane}, or
• a structured map: {someField=Joe, leafObject={someField=Jane}}.

Here's an example from their page:

public class Parent{
    private Child child;
    private String name; 
    // setters and getters are omitted
}

public class Child{
   private String name; 
   private List<String> nickNames;
   // setters and getters are omitted
}

Output will be:

{person.name=George, person.child.name=Jenna, person.child.nickNames[0]=Bimbo . . . etc}

A reverse transformer is also available.

Answer 7

With Java 8 you may try this :

public Map<String, Object> toKeyValuePairs(Object instance) {
    return Arrays.stream(Bean.class.getDeclaredMethods())
            .collect(Collectors.toMap(
                    Method::getName,
                    m -> {
                        try {
                            Object result = m.invoke(instance);
                            return result != null ? result : "";
                        } catch (Exception e) {
                            return "";
                        }
                    }));
}

Answer 8

Simply using reflection and Groovy :

def Map toMap(object) {             
return object?.properties.findAll{ (it.key != 'class') }.collectEntries {
            it.value == null || it.value instanceof Serializable ? [it.key, it.value] : [it.key,   toMap(it.value)]
    }   
}

def toObject(map, obj) {        
    map.each {
        def field = obj.class.getDeclaredField(it.key)
        if (it.value != null) {
            if (field.getType().equals(it.value.class)){
                obj."$it.key" = it.value
            }else if (it.value instanceof Map){
                def objectFieldValue = obj."$it.key"
                def fieldValue = (objectFieldValue == null) ? field.getType().newInstance() : objectFieldValue
                obj."$it.key" = toObject(it.value,fieldValue) 
            }
        }
    }
    return obj;
}

Answer 9

Use juffrou-reflect's BeanWrapper. It is very performant.

Here is how you can transform a bean into a map:

public static Map<String, Object> getBeanMap(Object bean) {
    Map<String, Object> beanMap = new HashMap<String, Object>();
    BeanWrapper beanWrapper = new BeanWrapper(BeanWrapperContext.create(bean.getClass()));
    for(String propertyName : beanWrapper.getPropertyNames())
        beanMap.put(propertyName, beanWrapper.getValue(propertyName));
    return beanMap;
}

I developed Juffrou myself. It's open source, so you are free to use it and modify. And if you have any questions regarding it, I'll be more than happy to respond.

Cheers

Carlos

Answer 10

You can use the java 8 stream filter collector properties,

public Map<String, Object> objectToMap(Object obj) {
    return Arrays.stream(YourBean.class.getDeclaredMethods())
            .filter(p -> !p.getName().startsWith("set"))
            .filter(p -> !p.getName().startsWith("getClass"))
            .filter(p -> !p.getName().startsWith("setClass"))
            .collect(Collectors.toMap(
                    d -> d.getName().substring(3),
                    m -> {
                        try {
                            Object result = m.invoke(obj);
                            return result;
                        } catch (Exception e) {
                            return "";
                        }
                    }, (p1, p2) -> p1)
            );
}

Answer 11

JSON, for example using XStream + Jettison, is a simple text format with key value pairs. It is supported for example by the Apache ActiveMQ JMS message broker for Java object exchange with other platforms / languages.

Answer 12

There is of course the absolute simplest means of conversion possible - no conversion at all!

instead of using private variables defined in the class, make the class contain only a HashMap which stores the values for the instance.

Then your getters and setters return and set values into and out of the HashMap, and when it is time to convert it to a map, voila! - it is already a map.

With a little bit of AOP wizardry, you could even maintain the inflexibility inherent in a bean by allowing you to still use getters and setters specific to each values name, without having to actually write the individual getters and setters.

Answer 13

You could use the Joda framework:

http://joda.sourceforge.net/

and take advantage of JodaProperties. This does stipulate that you create beans in a particular way however, and implement a specific interface. It does then however, allow you to return a property map from a specific class, without reflection. Sample code is here:

http://pbin.oogly.co.uk/listings/viewlistingdetail/0e78eb6c76d071b4e22bbcac748c57

Answer 14

If you do not want to hardcode calls to each getter and setter, reflection is the only way to call these methods (but it is not hard).

Can you refactor the class in question to use a Properties object to hold the actual data, and let each getter and setter just call get/set on it? Then you have a structure well suited for what you want to do. There is even methods to save and load them in the key-value form.

Answer 15

Add Jackson library

<dependency>
    <groupId>com.fasterxml.jackson.core</groupId>
    <artifactId>jackson-databind</artifactId>
    <version>2.6.3</version>
</dependency>

Then you could generate map using Object mapper.

ObjectMapper objectMapper = new ObjectMapper();

Map<String, Object> map = objectMapper.convertValue(
    yourJavaObject, 
    new TypeReference<Map<String, Object>>() {}
);

Answer 16

The best solution is to use Dozer. You just need something like this in the mapper file:

<mapping map-id="myTestMapping">
  <class-a>org.dozer.vo.map.SomeComplexType</class-a>
  <class-b>java.util.Map</class-b>
</mapping> 

And that's it, Dozer takes care of the rest!!!

Dozer Documentation URL

Answer 17

If you really really want performance you can go the code generation route.

You can do this on your on by doing your own reflection and building a mixin AspectJ ITD.

Or you can use Spring Roo and make a Spring Roo Addon. Your Roo addon will do something similar to the above but will be available to everyone who uses Spring Roo and you don't have to use Runtime Annotations.

I have done both. People crap on Spring Roo but it really is the most comprehensive code generation for Java.

Answer 18

One other possible way is here.

The BeanWrapper offers functionality to set and get property values (individually or in bulk), get property descriptors, and to query properties to determine if they are readable or writable.

Company c = new Company();
 BeanWrapper bwComp = BeanWrapperImpl(c);
 bwComp.setPropertyValue("name", "your Company");

Answer 19

With the help of Jackson library, I was able to find all class properties of type String/integer/double, and respective values in a Map class. (without using reflections api!)

TestClass testObject = new TestClass();
com.fasterxml.jackson.databind.ObjectMapper m = new com.fasterxml.jackson.databind.ObjectMapper();

Map<String,Object> props = m.convertValue(testObject, Map.class);

for(Map.Entry<String, Object> entry : props.entrySet()){
    if(entry.getValue() instanceof String || entry.getValue() instanceof Integer || entry.getValue() instanceof Double){
        System.out.println(entry.getKey() + "-->" + entry.getValue());
    }
}

Answer 20

My JavaDude Bean Annotation Processor generates code to do this.

http://javadude.googlecode.com

For example:

@Bean(
  createPropertyMap=true,
  properties={
    @Property(name="name"),
    @Property(name="phone", bound=true),
    @Property(name="friend", type=Person.class, kind=PropertyKind.LIST)
  }
)
public class Person extends PersonGen {}

The above generates superclass PersonGen that includes a createPropertyMap() method that generates a Map for all properties defined using @Bean.

(Note that I'm changing the API slightly for the next version -- the annotation attribute will be defineCreatePropertyMap=true)

Answer 21

You should write a generic transformation Service! Use generics to keep it type free (so you can convert every object to key=>value and back).

What field should be the key? Get that field from the bean and append any other non transient value in a value map.

The way back is pretty easy. Read key(x) and write at first the key and then every list entry back to a new object.

You can get the property names of a bean with the apache commons beanutils!

Answer 22

If it comes to a simple object tree to key value list mapping, where key might be a dotted path description from the object's root element to the leaf being inspected, it's rather obvious that a tree conversion to a key-value list is comparable to an object to xml mapping. Each element within an XML document has a defined position and can be converted into a path. Therefore I took XStream as a basic and stable conversion tool and replaced the hierarchical driver and writer parts with an own implementation. XStream also comes with a basic path tracking mechanism which - being combined with the other two - strictly leads to a solution being suitable for the task.

Answer 23

By using Gson,

1. Convert POJO object to Json

2. Convert Json to Map

       retMap = new Gson().fromJson(new Gson().toJson(object), 
               new TypeToken<HashMap<String, Object>>() {}.getType()
       );
   

Answer 24

We can use the Jackson library to convert a Java object into a Map easily.

<dependency>
   <groupId>com.fasterxml.jackson.core</groupId>
   <artifactId>jackson-databind</artifactId>
   <version>2.6.3</version>
</dependency>

If using in an Android project, you can add jackson in your app's build.gradle as follows:

implementation 'com.fasterxml.jackson.core:jackson-core:2.9.8'
implementation 'com.fasterxml.jackson.core:jackson-annotations:2.9.8'
implementation 'com.fasterxml.jackson.core:jackson-databind:2.9.8'

Sample Implementation

public class Employee {

    private String name;
    private int id;
    private List<String> skillSet;

    // getters setters
}

public class ObjectToMap {

 public static void main(String[] args) {

    ObjectMapper objectMapper = new ObjectMapper();

    Employee emp = new Employee();
    emp.setName("XYZ");
    emp.setId(1011);
    emp.setSkillSet(Arrays.asList("python","java"));

    // object -> Map
    Map<String, Object> map = objectMapper.convertValue(emp, 
    Map.class);
    System.out.println(map);

 }

}

Output:

{name=XYZ, id=1011, skills=[python, java]}