Converting a long integer to char array in C language?

Question

I want to convert this: int number = 12345678; to uint8_t numarray[] = "12345678";

How to make this possible? I will really appreciate your help.

Why `uint8_t` rather than `char` which is the normal type for a string? Anyway, use [snprintf](https://linux.die.net/man/3/snprintf) — kaylum, Oct 06 '22 at 05:30
I think you might be looking for this: https://stackoverflow.com/a/8257728/19592428 — Pavel Savchuk, Oct 06 '22 at 05:35

score 0 · Answer 1 · answered Oct 06 '22 at 05:43

0

#include <stdio.h>
#include <stdlib.h>
#include <string.h>
 
int main()
{
    
    int number = 12345678;
    
    char numberArray[10] = {0};
    
    itoa(number,numberArray,10);
    
    printf("Number Array = %s",numberArray);

    return 0;
}

I think this code will do what you want

answered Oct 06 '22 at 05:43

Mehmet Muhammed Karatokuş

1

1

Note that `itoa` is not a standard C function and will not be available in all cases. – kaylum Oct 06 '22 at 05:52
sprintf(numberArray,"%d" ,number); – ulix Oct 06 '22 at 06:58

Converting a long integer to char array in C language?

1 Answers1