I just started assembly, so i'm having a hard time understanding
This is a full assembly code of function F1
Dump of assembler code for function F1:
0x000000000000114a <+0>: push %rbp
0x000000000000114b <+1>: push %rbx
0x000000000000114c <+2>: sub $0x8,%rsp
0x0000000000001150 <+6>: mov %edi,%ebx
0x0000000000001152 <+8>: test %edi,%edi
0x0000000000001154 <+10>: je 0x115b <F1+17>
0x0000000000001156 <+12>: cmp $0x1,%edi
0x0000000000001159 <+15>: jne 0x1164 <F1+26>
0x000000000000115b <+17>: mov %ebx,%eax
0x000000000000115d <+19>: add $0x8,%rsp
0x0000000000001161 <+23>: pop %rbx
0x0000000000001162 <+24>: pop %rbp
0x0000000000001163 <+25>: retq
0x0000000000001164 <+26>: lea -0x1(%rdi),%edi
0x0000000000001167 <+29>: callq 0x114a <F1>
0x000000000000116c <+34>: mov %eax,%ebp
0x000000000000116e <+36>: lea -0x2(%rbx),%edi
0x0000000000001171 <+39>: callq 0x114a <F1>
0x0000000000001176 <+44>: lea 0x0(%rbp,%rax,1),%ebx
0x000000000000117a <+48>: jmp 0x115b <F1+17>
End of assembler dump.
this part is where i want to know
0x000000000000114a <+0>: push %rbp
0x000000000000114b <+1>: push %rbx
0x000000000000114c <+2>: sub $0x8,%rsp
I know that %rsp is a pointer pointing to the top position on the stack, but I gave rbp a value from <+0> to push %rbp, but %rsp did not.
Did you automatically change %rsp to a pointer to %rbx because of push %rbx on <+1>?
