What is equivalent of Matlab nan( ) in python?

Question

this is my MATLAB code with the following output:

pad=nan(1,5)

pad =

   NaN   NaN   NaN   NaN   NaN

I want to do the same operation in python, I tried np.isnan(1,6) but this is not working. what should I used to get the same results. thank you

i tried this like np.nan(5) also np.nan(1,5) but it show this error: TypeError: 'float' object is not callable — , Oct 09 '22 at 13:37

score 2 · Accepted Answer · answered Oct 09 '22 at 13:30

2

You can use np.full() to create a multi-dimensional array pre-populated with the same values:

np.full((1, 5), np.nan)

which produces:

array([[nan, nan, nan, nan, nan]])

answered Oct 09 '22 at 13:30

sj95126

1

why not np.full(5, np.nan) ? this give us array([nan, nan, nan, nan, nan]) – Oct 09 '22 at 13:42
1

@user20191650: Because the two-argument form of Matlab's `nan()` returns a multi-dimensional array. – sj95126 Oct 09 '22 at 13:43

score 0 · Answer 2 · answered Oct 09 '22 at 13:33

0

You can use numpy.zeros(N) + numpy.nan, where N is the number of NaN you want in your array.

import numpy as np

N = 6
nan_array = np.zeros(N) + np.nan

Will produce the following array -

[array([nan, nan, nan, nan, nan, nan])]

answered Oct 09 '22 at 13:33

Faruk Ahmad

2 Answers2