C# Infer generic type based on passing a delegate

Question

I have the following code:

public static class X
{
    public static C Test<A,B,C>(this A a, Func<B,C> f)
        where C:class
    {
        return null;
    }

}

public class Bar
{
    public Bar()
    {
        this.Test(foo); //this doesn't compile
        this.Test((Func<int, string>)foo);
        this.Test((int q) => "xxx");
    }

    string foo(int a) { return ""; }
}

Why doesn't the marked line compile? Does it have something to do with return type not being part of the signature?
But the third line does compile, which makes me guess the compiler turns it into something similiar to the second line...

possible duplicate of [C# 3.0 generic type inference - passing a delegate as a function parameter](http://stackoverflow.com/questions/407983/c-3-0-generic-type-inference-passing-a-delegate-as-a-function-parameter) Read those answers, they will give a detailed explanation. — Doc Brown, Sep 13 '11 at 10:48

score 8 · Accepted Answer · answered Sep 13 '11 at 10:50

Basically, the type inference process described in section 7.5.2 of the spec is relatively weak when it comes to method group conversions. In the annotated standard, in section 7.5.2.6 which talks about Output Type Inferences - including method groups - there's an annotation from Vladimir Reshetnikov stating:

This step [method group output type inference] applies only if all method type parameters occurring in the delegate parameter types are already fixed. Overload resolution does not try to select the best method based on incomplete type information.

I believe that's exactly the problem here - sure, you've only actually got one method you can call and the method group only contains a single method, but the type inference process isn't quite powerful enough to tie the two together.

C# Infer generic type based on passing a delegate

1 Answers1