Lines in if statement printing even when triggering another statement. Python 3.0

Question

print("Example intro.")

answer = input("Write one, two, three, four or five (caps or no caps.)").lower().strip()

if answer == "one" or "One" or "ONE":
    print("1")                      
    
if answer == "two" or "Two" or "TWO":
   print("2")

if answer == "three" or "Three" or "THREE":
    print("3")

if answer ==  "four" or "Four" or "FOUR":
    print ("4")

if answer == "five" or "Five" or "FIVE":
    print ("5")

When you run the code it shows 1 2 3 4 5 as the result for all of the answers. Please tell me howe to fix this because Friday 14th October 2022 (GMT) is my deadline.

(This isn't the full script BTW)

To solve it yourself simplify things: `if answer == "one":`. By the way, that would be sufficient because of `lower`. You are missing `(answer = ...) or ((answer = ...)`. — Joop Eggen, Oct 10 '22 at 18:57

score 0 · Answer 1 · answered Oct 10 '22 at 18:56

In python any non-zero value evaluates to true.

# the "One" by itself evaluates to true

if answer == "one" or "One" or "ONE":
    print("1")

needs to be rewritten as

if (answer == "one") or (answer == "One") or (answer == "ONE"):
    print("1")

Lines in if statement printing even when triggering another statement. Python 3.0

1 Answers1