what Is the true form for this "#${variable}"

Asked Oct 12 '22 at 07:43

Active Oct 12 '22 at 07:43

Viewed 28 times

I can't figure it out. Im trying to add type inside $("#") but can do this.Thanks For Helping me !

type = $(this).attr("id");
$("#${type}").html($(this).html());

asked Oct 12 '22 at 07:43

ruhatozcan

3

Do you mean [template literals](https://developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/Template_literals)? If so it only works with that specific backtick. – Lain Oct 12 '22 at 07:44
these 2 row in different function can't do $(this) – ruhatozcan Oct 12 '22 at 07:46
2

This only makes sense if you're using duplicate IDs - don't use duplicate IDs. – freedomn-m Oct 12 '22 at 07:46
1

"*these 2 row in different function can't do $(this)*" - but you have 2 `$(this)` in the same code? confusing. – freedomn-m Oct 12 '22 at 07:47
i am trying to get another div by id like $("#id") but instead of id I am trying to write a variable like ${type} when I try $("# ${type}") not working – ruhatozcan Oct 12 '22 at 07:50
4

Because you are using the wrong backticks. Check the first link or the linked duplicate. – Lain Oct 12 '22 at 07:50
1

Instead of `$("#${type}")` use `$(\`#${type}\`)` – freedomn-m Oct 12 '22 at 07:53

0 Answers0