Parse error: syntax error, unexpected token "echo", expecting ")"

Question

I just tried to add this line

data-tippy-content="<?php echo get_post_meta($post->ID, 'Author', true); ?>"

into some php code. The result is this:

<?php
the_title( '<a href="' . esc_url( get_permalink() ) . '" rel="bookmark" class="modal-link"  data-tippy-content="'echo get_post_meta($post->ID, 'Author', true)'">', '</a>' );
?>

Any idea what I did wrong here?

The error message I got is:

Parse error: syntax error, unexpected token "echo", expecting ")"

Strange. I removed the `echo` and now I'm getting this warning: `unexpected identifier "get_post_meta", expecting ")" ` — alexander, Oct 16 '22 at 18:30
You need to concat it `data-tippy-content="' . get_post_meta($post->ID, 'Author', true) . '">',` — Markus Zeller, Oct 16 '22 at 18:39

FakeCoder01 · Answer 1 · 2022-10-16T18:41:53.277

-1

<?php the_title( '<a href="'. esc_url( get_permalink() ) .'" rel="bookmark" class="modal-link"  data-tippy-content="' . get_post_meta($post->ID, "Author", true). '">,</a>' );  ?>

edited Oct 16 '22 at 18:41

answered Oct 16 '22 at 18:39

FakeCoder01

13
3

Thanks, had to add two quoutation marks to make it work `>','` – alexander Oct 16 '22 at 18:53

Parse error: syntax error, unexpected token "echo", expecting ")"

1 Answers1