how to append to list below example given and output also?

Question

This is the data:

data=[{"id":1,"name":"vikash","roll":39},{"id":2,"name":"kumar","roll":3}] 

data2=[{"hobby":"football","food":"any"},{"hobby":"basketball","food":"any"}]
list1=[]

expected Output:

list1:[{"name":"vikash","roll":39,"hobby":"football","food":"any"},{"name":"kumar","roll":3,"hobby":"basketball","food":"any"}]

Please help me!

Hi, the result is needed in what Language? Javascript or Python? — Lucas Paixão, Oct 17 '22 at 11:28
Try to create a [minimal reproducible example](https://stackoverflow.com/help/minimal-reproducible-example). There is not enough information here to provide a definitive answer [How to Ask](https://stackoverflow.com/help/how-to-ask). — RenaudC5, Oct 17 '22 at 11:29

score 0 · Answer 1 · answered Oct 17 '22 at 11:41

Providing both lists are the same length, you're happy there are no key conflicts and you're using Python...

data=[{"id":1,"name":"vikash","roll":39},{"id":2,"name":"kumar","roll":3}]

data2=[{"hobby":"football","food":"any"},{"hobby":"basketball","food":"any"}]


list1 = []

for k, v in enumerate(data):
    list1.append({**v, **data2[k]})

print(list1)

However in the future please be more concise when asking your questions.

Specify the language
Don't include redundant tags (eg - this question has nothing to do with Django)
Tell us what you've tried!

Also... the "please help me" line isn't required. The whole purpose of this community is to help each other so again this is redundant!

score 0 · Answer 2 · answered Oct 17 '22 at 11:44

A simpler to understand solution

data=[{"id":1,"name":"vikash","roll":39},{"id":2,"name":"kumar","roll":3}] 

data2=[{"hobby":"football","food":"any"},{"hobby":"basketball","food":"any"}]
list1=[]


for i in range(len(data)):
    del data[i]['id']
    d_main = {}
    d_main.update(data[i])
    d_main.update(data2[i])
    list1.append(d_main)
    
print(list1)

how to append to list below example given and output also?

2 Answers2