How to change the value of an index in a list that exist in a list

Asked Oct 17 '22 at 17:50

Active Oct 17 '22 at 17:55

Viewed 19 times

I have a list like named as modified and can be seen below;

modified = [["a"]*3]*3

If I want to change the value of first index in first element with "1", I use the codeblock below;

modified[0][0] = int(1)

However, the result is shown as [[1, 'a', 'a'], [1, 'a', 'a'], [1, 'a', 'a']].

I was expecting the result as [[1, 'a', 'a'], ['a', 'a', 'a'], ['a', 'a', 'a']]. How can I solve this issue?

edited Oct 17 '22 at 17:55

asked Oct 17 '22 at 17:50

murcielago

2

My bet, you created `modified` using `modified = [['a', 'a', 'a']]*3` or similar – mozway Oct 17 '22 at 17:54
It looks like you added the same list `['a', 'a', 'a']` three times to the list `modified`. Could please show how you really create the outer list? – Matthias Oct 17 '22 at 17:54
Are you sure you are declaring `modified` the same way you mentioned in your code? – Rahul K P Oct 17 '22 at 17:54
Yes, it was created with [["a"]*3]*3 – murcielago Oct 17 '22 at 17:55
Then you have 3 times the **same** sublist in your outer list – mozway Oct 17 '22 at 17:58

0 Answers0