How to get generator function to print

Question

Edit: I saw a post about including brackets to make a list. In this case, where would I insert said brackets? Sorry, newbie.

I have a function to generate combinations of any given number range but I need to print out or list all the possible combinations. Instead I'm getting this:

<generator object combinations at 0x00000175A6796040>

The source code:

def combinations(iterable,r):
    pool = tuple(iterable)
    n = len(pool)
    if r > n:
        return
    indices = list(range(r))
    yield tuple(pool[i] for i in indices)
    while True:
        for i in reversed(range(r)):
            if indices[i] !=i + n - r:
                break
        else:
            return
        indices[i] += 1
        for j in range(i+1,r):
            indices[j] = indices[j-1] + 1
        yield tuple(pool[i] for i in indices)

combinations(range(4),5)

I would like a list of all number combinations from 0 to 4 in 5-digit numbers. How do I call the function in a way that allows me to view the actual combinations?

Does this answer your question? [How to print a generator expression?](https://stackoverflow.com/questions/5164642/how-to-print-a-generator-expression) — ms12, Oct 19 '22 at 12:56
That works. However, I get back an empty list. Can't there be combinations of 5 digit numbers within the specified range? — Raginmund_Odinson, Oct 19 '22 at 13:47

score 0 · Accepted Answer · answered Oct 19 '22 at 14:08

Generators and iterators are lazily evaluated functions, hence the use of the yield keyword. Therefore, to get the next value from a generator or iterator, say gen, we call next(gen). Some other comments on your post are saying that you should just cast your generator to a list, which is fine but may defeat the purpose of using a generator.

Additionally, your code won't produce anything if you call next() or cast to a list. This is because you check for if r > n, which it is when range(4) and 5 are passed in as arguments. Ultimately, you code immediately exits your function.

If you wish for your code to output all combinations as 5 digit numbers given your input, you're code must allow for repeat digits in the output combinations.

Therefore, rather use:

def combinations(iterable,r):
    pool = tuple(iterable)
    start = tuple(pool[0] for i in range(r))
    yield start
    while True:
        for i in reversed(range(r)):
            if start[i] != pool[-1]:
                break
        else:
            return
        start = list(start)
        start[i] = pool[pool.index(start[i])+1]
        for j in range(i+1,r):
            start[j] = pool[0]
        yield tuple(start)

To call and get all combinations do either of the following:

gen = combinations(range(4),5)
    while True:
        try:
            print(next(gen))
        except StopIteration:
            break

, or

gen = combinations(range(4),5)
list(gen)

, or

for i in combinations(range(4),5):
    print(i)

How to get generator function to print

1 Answers1