Using const references as lvalues

Asked Oct 19 '22 at 17:44

Active Oct 19 '22 at 20:08

Viewed 63 times

A few examples:

const char* chars = returnschars();

const std::string str(chars);
const std::string& str_ref(chars);

Is there a difference between str and str_ref and what exactly is different?

const auto& foo = createfoo();
const auto& bar = createbarbasedonfoo(foo)
const auto& pair = std::make_pair(foo, bar);

Why does this work?
Who owns the object that foo is referencing?

const int& i = 15;
const int j = 15;

Again, is there a difference between i and j and what exactly is different?

Could I just only use const references instead of const?

edited Oct 19 '22 at 19:50

asked Oct 19 '22 at 17:44

Rasmus-123

1

It seems like you're asking about temporary lifetime extension – Nathan Pierson Oct 19 '22 at 17:49
`const auto& wrapper = wrapper(foo);` should not compile. – apple apple Oct 19 '22 at 18:44
@NathanPierson Thanks, I'll have to do some reading and playing around, but that looks like the right place. – Rasmus-123 Oct 19 '22 at 18:54
@appleapple What I did was ```const auto& foo = create_foo(); const auto& bar = create_bar_based_on_foo(foo); const auto& baz = std::make_pair(foo, bar); ``` – Rasmus-123 Oct 19 '22 at 18:55
@Rasmus-123 you can [edit] the post to correct the information. – apple apple Oct 19 '22 at 19:17

0 Answers0