Print all the "a" of a string on python

Question

I'm trying to print all the "a" or other characters from an input string. I'm trying it with the .find() function but just print one position of the characters. How do I print all the positions where is an specific character like "a"

Does this answer your question? [How to find all occurrences of a substring?](https://stackoverflow.com/questions/4664850/how-to-find-all-occurrences-of-a-substring) — luk2302, Oct 20 '22 at 10:16

score 1 · Accepted Answer · answered Oct 20 '22 at 10:23

1

You can use find with while loop

a = "aabababaa"
k = 0
while True:
    k = a.find("a", k) # This is saying to start from where you left
    if k == -1:
        break
    k += 1
    print(k)

answered Oct 20 '22 at 10:23

Deepak Tripathi

3,175
1
8
21

score 1 · Answer 2 · answered Oct 20 '22 at 10:34

1

This is also possible with much less amount of code if you don't care where you want to start.

a = "aabababaa"

for i, c in enumerate(a): # i = Index, c = Character. Using the Enumerate()
  if ("a" in c):
    print(i)

answered Oct 20 '22 at 10:34

ThisQRequiresASpecialist

929
4
19

score 0 · Answer 3 · answered Oct 20 '22 at 13:43

Some first-get-all-matches-and-then-print versions:

With a list comprehension:

s = "aslkbasaaa"

CHAR = "a"
pos = [i for i, char in enumerate(s) if char == CHAR]
print(*pos, sep='\n')

or with itertools and composition of functions

from itertools import compress

s = "aslkbasaaa"

CHAR = "a"
pos = compress(range(len(s)), map(CHAR.__eq__, s))
print(*pos, sep='\n')

Print all the "a" of a string on python

3 Answers3