Passing a enum as a function parameter | C

Question

I need to track where the function is calling too, so I made an enum with a list of the drivers I wish to track.

enum FPGA_IO_Type{

   A429_RX = 0,

   A429_TX = 1,

   A717_RX = 2,

   A717_TX = 3

};

now I want to put it as a function parameter

static void _function(otherData, enum FPGA_IO_Type)

and each function call looks something like this

_function(data, A429_RX);

However I get an error for "Parameter name omitted".

What am I doing wrong?

score 2 · Accepted Answer · answered Oct 20 '22 at 14:43

2

You are not giving it a name identifier, should be like:

static void _function(otherData, enum FPGA_IO_Type type)

likewise when you define a struct

struct Abc
{
   ...
}

you can put it as a parameter such as

void function(struct Abc abc)
{

}

Here enum FPGA_IO_Type and struct Abc are the types of the parameter and type and abc are the identifiers.

answered Oct 20 '22 at 14:43

Another option is using typedef declaration: `typedef enum FPGA_IO_Type { ... } FPGA_IO_Type_t` so the varilable is simply `FPGA_IO_Type_t` – Filippo Oct 20 '22 at 14:52
@Filippo Yes indeed – Özgür Güzeldereli Oct 20 '22 at 14:53

1 Answers1