When I print pow(2, 20), the output is: 1.04858e+06
#include<iostream>
#include<cmath>
using namespace std;
int main(){
cout << pow(2, 20) << endl;
return 0;
}
How can I turn the output back to 1048576?
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Achilles
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2Why don't you simply use an unsigned integer `(2u << 20)`? – πάντα ῥεῖ Oct 22 '22 at 07:24
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Have a look at `std::fixed`. But seriously... A power of 2 with `pow()`? – Scheff's Cat Oct 22 '22 at 07:24
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2@πάνταῥεῖ Shouldn't it be `(1u << 20)`? It should: [demo on coliru](http://coliru.stacked-crooked.com/a/ace4199fbde6a563). ;-) – Scheff's Cat Oct 22 '22 at 07:26
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@Scheff'sCat oops, yes of course :-) – πάντα ῥεῖ Oct 22 '22 at 07:29
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The problem here is that you're not passing a expression of an integral type to the `<<` operator, but `double`, see https://en.cppreference.com/w/cpp/numeric/math/pow – fabian Oct 22 '22 at 08:08
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`pow(2,20)` is not an integer. `pow` is not for integers, its for floating point numbers. `2 << 20` is an integer. – 463035818_is_not_an_ai Oct 22 '22 at 09:26