Python transform array 1D

Asked Oct 25 '22 at 20:00

Active Oct 25 '22 at 20:05

Viewed 42 times

I have a array which has this output and your type is cupy.ndarray:

x = array([[0],
       [0],
       [0],
       ...,
       [0],
       [0],
       [0]])

I want is output:

array([0, 0, 0, ..., 0, 0, 0])

I tried use transpose and np.expand_dims and had the outputs:

x.transpose()

# Output
array([[0, 0, 0, ..., 0, 0, 0]])

np.expand_dims(x, axis=1)

#Output
array([[[0, 0, 0, ..., 0, 0, 0]]])

asked Oct 25 '22 at 20:00

M.Souza

`[arr[0] for arr in x]` – It_is_Chris Oct 25 '22 at 20:03
1

If you just want to make it 1d, `x.flatten()` – jvx8ss Oct 25 '22 at 20:03
Do `x = x.reshape(-1)`. That tells is to keep the same number of elements but make it a 1D array instead of a 2D array. – Tim Roberts Oct 25 '22 at 20:03
1

or `x.ravel()` so many options. – Mark Oct 25 '22 at 20:04
or `x.T.squeeze()`... – ShlomiF Oct 25 '22 at 20:04
FWIW, `reshape` is quite efficient, because it doesn't change the array. It just changes the interpretation. – Tim Roberts Oct 25 '22 at 20:04
FWIW, `ravel()` is also normally a view into the same date. – Mark Oct 25 '22 at 20:08

0 Answers0