jquery validate - valid if hidden field has a value

Question

I need to validate a field based on the value of a hidden field. I tried this custom rule:

jQuery.validator.addMethod("cityselected", function() {
    if ($('#featureID').val() == "") return false;
    else return true;
});

cityselect: {
    required: true,
    cityselected: true
},

featureID is a hidden input which I need to check has a value. This doesnt seem to work though. Any ideas?

score 4 · Accepted Answer · answered Sep 15 '11 at 11:17

4

Add the class "required" to the hidden input.

answered Sep 15 '11 at 11:17

svnv

86
3

score 2 · Answer 2 · answered Jul 05 '13 at 08:51

2

If your plugin version is greater than 1.9, you'll have to explicitly add hidden to the validation process, like that when you initialize the plugin :

$("#form").validate({
  // Do not ignore hidden fields
  ignore: []
});

answered Jul 05 '13 at 08:51

Pouki

1,654
12
18

1

You are correct... this is the way to do it with the later versions of the plugin. However, in all fairness to the OP, this was not an option in 2011 when hidden fields were not ignored. – Sparky Jul 05 '13 at 15:47

jquery validate - valid if hidden field has a value

2 Answers2

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