Convert an 1D list into a 2D list of pairs

Question

I have the list:

[0, 15, 19, 26, 34, 62]

How would I go about converting it into the following?

[[0, 15], [19, 26], [34, 62]]

If your list is `l`, you can simply `pairs = list(zip(l[::2], l[1::2]))` or, if you really need the items to be lists as well, `pairs = [list(_) for _ in zip(l[::2], l[1::2])]`. — accdias, Nov 03 '22 at 14:06
normally users should show what they tried, even if it failed — OrenIshShalom, Nov 03 '22 at 14:13
... and here is another very _Pythonic_ but not so clear option: `pairs = [*map(list, zip(l[::2], l[1::2]))]`. — accdias, Nov 03 '22 at 14:16
@HMH1013, check my updated comments. I already suggested that as well. — accdias, Nov 03 '22 at 14:17
@accdias OK, I think we comment at the same time, so I didn't see your update. I have deleted. — HMH1013, Nov 03 '22 at 14:19

score 2 · Answer 1 · answered Nov 03 '22 at 14:09

2

You can use numpy:

import numpy as np

arr = [0, 15, 19, 26, 34, 62]
np.reshape(arr, (-1, 2))

output:

array([[ 0, 15],
       [19, 26],
       [34, 62]])

answered Nov 03 '22 at 14:09

Shahab Rahnama

Seems like an overkill using `numpy` for such a simple task. – accdias Nov 03 '22 at 14:10

score 0 · Answer 2 · answered Nov 03 '22 at 14:09

0

list = [0, 15, 19, 26, 34, 62]

new_list = []
for i in range(0, len(list), 2):
    new_list.append([list[i], list[i+1]])

answered Nov 03 '22 at 14:09

KillerRebooted

score 0 · Answer 3 · answered Nov 03 '22 at 14:10

0

A simple solution, list members must be even.

>>> a = [0, 15, 19, 26, 34, 62]
>>> [[a[l*2], a[l*2 + 1]] for l in range(int(len(a)/2))]
[[0, 15], [19, 26], [34, 62]]

answered Nov 03 '22 at 14:10

Yuri

3 Answers3