PHP's json_decode() with this JSON string

Question

I have this JSON string:

 {
    "name": "test task1",
    "desc": "test desc1",
    "id": "1"
}{
    "name": "test task1aaaa",
    "desc": "test desc1",
    "id": "2"
}

But it looks like it's not correct (JSONLint tells me) so PHP's json_decode()can't decode it. There's any way to separate the two JSON arrays into two strings (or into how much string the arrays are) for making json_decode decode them?

score 2 · Accepted Answer · answered Sep 15 '11 at 12:12

2

Assuming your intention is to have an array of two elements, your JSON should look like:

[
    {
        "name": "test task1",
        "desc": "test desc1",
        "id": "1"
    },{
        "name": "test task1aaaa",
        "desc": "test desc1",
        "id": "2"
    }
]

answered Sep 15 '11 at 12:12

karim79

339,989
67
413
406

Thanks, just made it correct, was generating the array wrong :D – pmerino Sep 15 '11 at 12:22

score 0 · Answer 2 · answered Sep 15 '11 at 12:15

0

the most straightforward

$str = ' {
    "name": "test task1",
    "desc": "test desc1",
    "id": "1"
}{
    "name": "test task1aaaa",
    "desc": "test desc1",
    "id": "2"
}';

var_dump(json_decode('['.str_replace('}{','},{',$str).']'));

answered Sep 15 '11 at 12:15

k102

7,861
7
49
69

score 0 · Answer 3 · answered Sep 15 '11 at 12:18

<?php
$str='{
    "name": "test task1",
    "desc": "test desc1",
    "id": "1"
}{
    "name": "test task1aaaa",
    "desc": "test desc1",
    "id": "2"
}';

$arrays = explode("{", $str);
foreach($arrays as &$arr) $arr='{'.$arr;

//decode
foreach ($arrays as $arr) print_r(json_decode($arr,true));

PHP's json_decode() with this JSON string

3 Answers3