I am trying to deploy a flask app in fly.io, but when execute flyctl launch in the terminal I get an error:
Error name argument or flag must be specified when not running interactively.
I don't see any other way to make a deployment in fly.io other than the console. I tried with a Dockerfile but flyctl launch continue throwing the same error.
Apparently flyctl believes you're not running its command-line tool interactively. That may or may not be a bug of flyctl itself, you can ask about that in the fly.io community.
The solution to this problem is to add the required information as parameters instead of being prompted for data entry. To my knowledge, you only need the name of the app you want to launch and the region code of the server location. The syntax for that can be found using the fly help launch command:
λ flyctl help launch
Create and configure a new app from source code or a Docker image.
Usage:
flyctl launch [flags]
Flags:
--auto-confirm Will automatically confirm changes when running non-interactively.
--build-arg strings Set of build time variables in the form of NAME=VALUE pairs. Can be specified multiple times.
--build-only Build but do not deploy
--build-secret strings Set of build secrets of NAME=VALUE pairs. Can be specified multiple times. See https://docs.docker.com/develop/develop-images/build_enhancements/#new-docker-build-secret-information
--build-target string Set the target build stage to build if the Dockerfile has more than one stage
--copy-config Use the configuration file if present without prompting
--detach Return immediately instead of monitoring deployment progress
--dockerfile string Path to a Dockerfile. Defaults to the Dockerfile in the working directory.
--dockerignore-from-gitignore If a .dockerignore does not exist, create one from .gitignore files
-e, --env strings Set of environment variables in the form of NAME=VALUE pairs. Can be specified multiple times.
--generate-name Always generate a name for the app, without prompting
-i, --image string The Docker image to deploy
--image-label string Image label to use when tagging and pushing to the fly registry. Defaults to "deployment-{timestamp}".
--local-only Only perform builds locally using the local docker daemon
--name string Name of the new app
--nixpacks Deploy using nixpacks to generate the image
--no-cache Do not use the build cache when building the image
--no-deploy Do not prompt for deployment
--now Deploy now without confirmation
-o, --org string The target Fly organization
--path string Path to the app source root, where fly.toml file will be saved (default ".")
--push Push image to registry after build is complete
-r, --region string The target region (see 'flyctl platform regions')
--remote-only Perform builds on a remote builder instance instead of using the local docker daemon
--strategy string The strategy for replacing running instances. Options are canary, rolling, bluegreen, or immediate. Default is canary, or rolling when max-per-region is set.
Global Flags:
-t, --access-token string Fly API Access Token
-j, --json json output
--verbose verbose output
In summary, the following command, executed in the directory of the app you want to launch on fly.io, should create an app called your-app-name in the Toronto, Canada location.
flyctl launch --name your-app-name --region yyz
