I have this working for loop, I want to use lambda that prints same results below
ids= [1,2,3,4,5,6,7]
val = [20,30,26,38,40,22,35]
list1=[]
for i,num in enumerate(val):
if num > 29:
list1.append(ids[i])
print("ids",list1)
#output ids [2, 4, 5, 7]
The code below throws and invalid syntax. I just want to get the element value not the index.
new_id=list(filter(lambda ids[i]:
val[i]>29, range(len(val))))
You can create lambda function to compare the value and return boolean, and call this function in your if condition. It's not a recommended way though E731 do not assign a lambda expression, use a def:
list1=[]
get_flag = lambda i:i>29
for i in val:
if get_flag(i):
list1.append(i)
print(list1)
[30, 38, 40, 35]
Or, you can just use filter builtin and pass a lambda function. It's equivalent List Comprehension is already there in another answer.
list(filter(lambda i: i>29, val))
[30, 38, 40, 35]
For updated question, to get the index, just iterate a range and filter out based on the values at given index:
>>> list(filter(lambda i: val[i]>29, range(len(val))))
[1, 3, 4, 6]
Do you want to use lambda function, Then it will be,
val = [20,30,26,38,40,22,35]
fun = lambda val: [v for v in val if v>29]
res = fun(val)
# [30, 38, 40, 35]
Not sure why lambdas, but I think you might be referring to something like this:
filtered = [x for x in val if x > 29]
This seems to be the most code-efficient way to achieve what you're asking.
