Enter if loop for no apparent reason?

Asked Nov 07 '22 at 23:36

Active Nov 07 '22 at 23:36

Viewed 21 times

mylist = [['apple',1],['banana',2],['byrne',3]]
x =  0
for y in mylist:
    print(x)
    print(mylist[x][0])
    if 'byrne' or 'apple' == mylist[x][0]:
        print('hi')
    x += 1

prints out:

0 apple hi 1 banana hi 2 byrne hi

The question: why does it enter the if loop for x = 1?

If i put just one string for entering the loop i get one hi, as expected.

asked Nov 07 '22 at 23:36

NiceIce

1

note: `if` is not a loop. – juanpa.arrivillaga Nov 07 '22 at 23:39
1

`if mylist[x][0] in ['byrne', 'apple']:`. Your code is being evaluated `'byrne' or OTHERSTUFF` and is always true since `bool('byrne')` evaluates as true. – MYousefi Nov 07 '22 at 23:40
@Nice In other words, Python does not interpret `a or b == c`as being the same as `(a == c) or (b == c)`. – Ben Grossmann Nov 07 '22 at 23:44

Enter if loop for no apparent reason?

0 Answers0