Why is the value of a variable (var1) being changed when I change the value of another variable (var2) that I previously had assigned it to (var2=var1

Asked Nov 09 '22 at 03:40

Active Nov 09 '22 at 03:42

Viewed 18 times

I am creating a list, x, and assigning another variable b to x. When I change the value of the first item in b, it is also changing the value of the first item in x.

This is the code I am executing.

x = [1]
b = x
b[0] = 2
print(x)

It is printing '[2]'

I expected the value of x to remain unchanged. I thought the code would print '[1]'

edited Nov 09 '22 at 03:42

asked Nov 09 '22 at 03:40

paintingunicorn

`b=x` doesn't make a copy, it just gives you two different ways to refer to the same list object. – Mark Ransom Nov 09 '22 at 03:44
because `b` and `x` *are referring to the same list object*. That is what `b = x` *does*. Check out: https://nedbatchelder.com/text/names.html – juanpa.arrivillaga Nov 09 '22 at 04:53

Why is the value of a variable (var1) being changed when I change the value of another variable (var2) that I previously had assigned it to (var2=var1

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