Why doesn't the count() method work for overlapping substrings?

Asked Nov 09 '22 at 04:25

Active Nov 09 '22 at 04:38

Viewed 28 times

This is my code:

a = 'BANANAAAS'
sub='AA'

print(a.count(sub))

Why does it not print 2 as an answer since the substring appears 2 times? The first one begining in a[5] and the other begining in a[6].

This was a part of a larger problem where I have to generate and count all the substring in a string depending if it begins with a vowel or not.

edited Nov 09 '22 at 04:38

Gino Mempin

asked Nov 09 '22 at 04:25

user20455796

1

It starts counting after the end of matching the first AA. – Mateen Ulhaq Nov 09 '22 at 04:30
As to how to do it instead: [String count with overlapping occurrences](https://stackoverflow.com/q/2970520/2745495) – Gino Mempin Nov 09 '22 at 04:33
why don't you loop like this `[a.count('AA', idx) for idx in range(len(a))] ` – Deepak Tripathi Nov 09 '22 at 04:35
2

`help(str.count)` says _Return the number of non-overlapping occurrences of substring sub in string_ (Note: non-overlapping) – tdelaney Nov 09 '22 at 04:38

0 Answers0