How to sort an array in Bash

Question

I have an array in Bash, for example:

array=(a c b f 3 5)

I need to sort the array. Not just displaying the content in a sorted way, but to get a new array with the sorted elements. The new sorted array can be a completely new one or the old one.

Answer 1

You don't really need all that much code:

IFS=$'\n' sorted=($(sort <<<"${array[*]}"))
unset IFS

Supports whitespace in elements (as long as it's not a newline), and works in Bash 3.x.

e.g.:

$ array=("a c" b f "3 5")
$ IFS=$'\n' sorted=($(sort <<<"${array[*]}")); unset IFS
$ printf "[%s]\n" "${sorted[@]}"
[3 5]
[a c]
[b]
[f]

Note: @sorontar has pointed out that care is required if elements contain wildcards such as * or ?:

The sorted=($(...)) part is using the "split and glob" operator. You should turn glob off: set -f or set -o noglob or shopt -op noglob or an element of the array like * will be expanded to a list of files.

What's happening:

The result is a culmination six things that happen in this order:

1. IFS=$'\n'
2. "${array[*]}"
3. <<<
4. sort
5. sorted=($(...))
6. unset IFS

First, the IFS=$'\n'

This is an important part of our operation that affects the outcome of 2 and 5 in the following way:

Given:

• "${array[*]}" expands to every element delimited by the first character of IFS
• sorted=() creates elements by splitting on every character of IFS

IFS=$'\n' sets things up so that elements are expanded using a new line as the delimiter, and then later created in a way that each line becomes an element. (i.e. Splitting on a new line.)

Delimiting by a new line is important because that's how sort operates (sorting per line). Splitting by only a new line is not-as-important, but is needed preserve elements that contain spaces or tabs.

The default value of IFS is a space, a tab, followed by a new line, and would be unfit for our operation.

Next, the sort <<<"${array[*]}" part

<<<, called here strings, takes the expansion of "${array[*]}", as explained above, and feeds it into the standard input of sort.

With our example, sort is fed this following string:

a c
b
f
3 5

Since sort sorts, it produces:

3 5
a c
b
f

Next, the sorted=($(...)) part

The $(...) part, called command substitution, causes its content (sort <<<"${array[*]}) to run as a normal command, while taking the resulting standard output as the literal that goes where ever $(...) was.

In our example, this produces something similar to simply writing:

sorted=(3 5
a c
b
f
)

sorted then becomes an array that's created by splitting this literal on every new line.

Finally, the unset IFS

This resets the value of IFS to the default value, and is just good practice.

It's to ensure we don't cause trouble with anything that relies on IFS later in our script. (Otherwise we'd need to remember that we've switched things around--something that might be impractical for complex scripts.)

Answer 2

Original response:

array=(a c b "f f" 3 5)
readarray -t sorted < <(for a in "${array[@]}"; do echo "$a"; done | sort)

output:

$ for a in "${sorted[@]}"; do echo "$a"; done
3
5
a
b
c
f f

Note this version copes with values that contains special characters or whitespace (except newlines)

Note readarray is supported in bash 4+.

---

Edit Based on the suggestion by @Dimitre I had updated it to:

readarray -t sorted < <(printf '%s\0' "${array[@]}" | sort -z | xargs -0n1)

which has the benefit of even understanding sorting elements with newline characters embedded correctly. Unfortunately, as correctly signaled by @ruakh this didn't mean the the result of readarray would be correct, because readarray has no option to use NUL instead of regular newlines as line-separators.

Answer 3

If you don't need to handle special shell characters in the array elements:

array=(a c b f 3 5)
sorted=($(printf '%s\n' "${array[@]}"|sort))

With bash you'll need an external sorting program anyway.

With zsh no external programs are needed and special shell characters are easily handled:

% array=('a a' c b f 3 5); printf '%s\n' "${(o)array[@]}" 
3
5
a a
b
c
f

ksh has set -s to sort ASCIIbetically.

Answer 4

Here's a pure Bash quicksort implementation:

#!/bin/bash

# quicksorts positional arguments
# return is in array qsort_ret
qsort() {
   local pivot i smaller=() larger=()
   qsort_ret=()
   (($#==0)) && return 0
   pivot=$1
   shift
   for i; do
      # This sorts strings lexicographically.
      if [[ $i < $pivot ]]; then
         smaller+=( "$i" )
      else
         larger+=( "$i" )
      fi
   done
   qsort "${smaller[@]}"
   smaller=( "${qsort_ret[@]}" )
   qsort "${larger[@]}"
   larger=( "${qsort_ret[@]}" )
   qsort_ret=( "${smaller[@]}" "$pivot" "${larger[@]}" )
}

Use as, e.g.,

$ array=(a c b f 3 5)
$ qsort "${array[@]}"
$ declare -p qsort_ret
declare -a qsort_ret='([0]="3" [1]="5" [2]="a" [3]="b" [4]="c" [5]="f")'

This implementation is recursive… so here's an iterative quicksort:

#!/bin/bash

# quicksorts positional arguments
# return is in array qsort_ret
# Note: iterative, NOT recursive! :)
qsort() {
   (($#==0)) && return 0
   local stack=( 0 $(($#-1)) ) beg end i pivot smaller larger
   qsort_ret=("$@")
   while ((${#stack[@]})); do
      beg=${stack[0]}
      end=${stack[1]}
      stack=( "${stack[@]:2}" )
      smaller=() larger=()
      pivot=${qsort_ret[beg]}
      for ((i=beg+1;i<=end;++i)); do
         if [[ "${qsort_ret[i]}" < "$pivot" ]]; then
            smaller+=( "${qsort_ret[i]}" )
         else
            larger+=( "${qsort_ret[i]}" )
         fi
      done
      qsort_ret=( "${qsort_ret[@]:0:beg}" "${smaller[@]}" "$pivot" "${larger[@]}" "${qsort_ret[@]:end+1}" )
      if ((${#smaller[@]}>=2)); then stack+=( "$beg" "$((beg+${#smaller[@]}-1))" ); fi
      if ((${#larger[@]}>=2)); then stack+=( "$((end-${#larger[@]}+1))" "$end" ); fi
   done
}

In both cases, you can change the order you use: I used string comparisons, but you can use arithmetic comparisons, compare wrt file modification time, etc. just use the appropriate test; you can even make it more generic and have it use a first argument that is the test function use, e.g.,

#!/bin/bash

# quicksorts positional arguments
# return is in array qsort_ret
# Note: iterative, NOT recursive! :)
# First argument is a function name that takes two arguments and compares them
qsort() {
   (($#<=1)) && return 0
   local compare_fun=$1
   shift
   local stack=( 0 $(($#-1)) ) beg end i pivot smaller larger
   qsort_ret=("$@")
   while ((${#stack[@]})); do
      beg=${stack[0]}
      end=${stack[1]}
      stack=( "${stack[@]:2}" )
      smaller=() larger=()
      pivot=${qsort_ret[beg]}
      for ((i=beg+1;i<=end;++i)); do
         if "$compare_fun" "${qsort_ret[i]}" "$pivot"; then
            smaller+=( "${qsort_ret[i]}" )
         else
            larger+=( "${qsort_ret[i]}" )
         fi
      done
      qsort_ret=( "${qsort_ret[@]:0:beg}" "${smaller[@]}" "$pivot" "${larger[@]}" "${qsort_ret[@]:end+1}" )
      if ((${#smaller[@]}>=2)); then stack+=( "$beg" "$((beg+${#smaller[@]}-1))" ); fi
      if ((${#larger[@]}>=2)); then stack+=( "$((end-${#larger[@]}+1))" "$end" ); fi
   done
}

Then you can have this comparison function:

compare_mtime() { [[ $1 -nt $2 ]]; }

and use:

$ qsort compare_mtime *
$ declare -p qsort_ret

to have the files in current folder sorted by modification time (newest first).

NOTE. These functions are pure Bash! no external utilities, and no subshells! they are safe wrt any funny symbols you may have (spaces, newline characters, glob characters, etc.).

NOTE2. The test [[ $i < $pivot ]] is correct. It uses the lexicographical string comparison. If your array only contains integers and you want to sort numerically, use ((i < pivot)) instead. _{Please don't edit this answer to change that. It has already been edited (and rolled back) a couple of times. The test I gave here is correct and corresponds to the output given in the example: the example uses both strings and numbers, and the purpose is to sort it in lexicographical order. Using ((i < pivot)) in this case is wrong.}

Answer 5

tl;dr:

Sort array a_in and store the result in a_out (elements must not have embedded newlines^[1] ):

Bash v4+:

readarray -t a_out < <(printf '%s\n' "${a_in[@]}" | sort)

Bash v3:

IFS=$'\n' read -d '' -r -a a_out < <(printf '%s\n' "${a_in[@]}" | sort)

Advantages over antak's solution:

• You needn't worry about accidental globbing (accidental interpretation of the array elements as filename patterns), so no extra command is needed to disable globbing (set -f, and set +f to restore it later).

• You needn't worry about resetting IFS with unset IFS.^[2]

---

Optional reading: explanation and sample code

The above combines Bash code with external utility sort for a solution that works with arbitrary single-line elements and either lexical or numerical sorting (optionally by field):

• Performance: For around 20 elements or more, this will be faster than a pure Bash solution - significantly and increasingly so once you get beyond around 100 elements.
  ^{(The exact thresholds will depend on your specific input, machine, and platform.)}

  • The reason it is fast is that it avoids Bash loops.

• printf '%s\n' "${a_in[@]}" | sort performs the sorting (lexically, by default - see sort's POSIX spec):

  • "${a_in[@]}" safely expands to the elements of array a_in as individual arguments, whatever they contain (including whitespace).

  • printf '%s\n' then prints each argument - i.e., each array element - on its own line, as-is.

• Note the use of a process substitution (<(...)) to provide the sorted output as input to read / readarray (via redirection to stdin, <), because read / readarray must run in the current shell (must not run in a subshell) in order for output variable a_out to be visible to the current shell (for the variable to remain defined in the remainder of the script).

• Reading sort's output into an array variable:

  • Bash v4+: readarray -t a_out reads the individual lines output by sort into the elements of array variable a_out, without including the trailing \n in each element (-t).

  • Bash v3: readarray doesn't exist, so read must be used:
    IFS=$'\n' read -d '' -r -a a_out tells read to read into array (-a) variable a_out, reading the entire input, across lines (-d ''), but splitting it into array elements by newlines (IFS=$'\n'. $'\n', which produces a literal newline (LF), is a so-called ANSI C-quoted string).
    (-r, an option that should virtually always be used with read, disables unexpected handling of \ characters.)

Annotated sample code:

#!/usr/bin/env bash

# Define input array `a_in`:
# Note the element with embedded whitespace ('a c')and the element that looks like
# a glob ('*'), chosen to demonstrate that elements with line-internal whitespace
# and glob-like contents are correctly preserved.
a_in=( 'a c' b f 5 '*' 10 )

# Sort and store output in array `a_out`
# Saving back into `a_in` is also an option.
IFS=$'\n' read -d '' -r -a a_out < <(printf '%s\n' "${a_in[@]}" | sort)
# Bash 4.x: use the simpler `readarray -t`:
# readarray -t a_out < <(printf '%s\n' "${a_in[@]}" | sort)

# Print sorted output array, line by line:
printf '%s\n' "${a_out[@]}"

Due to use of sort without options, this yields lexical sorting (digits sort before letters, and digit sequences are treated lexically, not as numbers):

*
10
5
a c
b
f

If you wanted numerical sorting by the 1st field, you'd use sort -k1,1n instead of just sort, which yields (non-numbers sort before numbers, and numbers sort correctly):

*
a c
b
f
5
10

---

^{[1] To handle elements with embedded newlines, use the following variant (Bash v4+, with GNU sort):
readarray -d '' -t a_out < <(printf '%s\0' "${a_in[@]}" | sort -z).
Michał Górny's helpful answer has a Bash v3 solution.}

^{[2] While IFS is set in the Bash v3 variant, the change is scoped to the command.
By contrast, what follows IFS=$'\n'  in antak's answer is an assignment rather than a command, in which case the IFS change is global.}

Answer 6

Another solution that uses external sort and copes with any special characters (except for NULs :)). Should work with bash-3.2 and GNU or BSD sort (sadly, POSIX doesn't include -z).

local e new_array=()
while IFS= read -r -d '' e; do
    new_array+=( "${e}" )
done < <(printf "%s\0" "${array[@]}" | LC_ALL=C sort -z)

First look at the input redirection at the end. We're using printf built-in to write out the array elements, zero-terminated. The quoting makes sure array elements are passed as-is, and specifics of shell printf cause it to reuse the last part of format string for each remaining parameter. That is, it's equivalent to something like:

for e in "${array[@]}"; do
    printf "%s\0" "${e}"
done

The null-terminated element list is then passed to sort. The -z option causes it to read null-terminated elements, sort them and output null-terminated as well. If you needed to get only the unique elements, you can pass -u since it is more portable than uniq -z. The LC_ALL=C ensures stable sort order independently of locale — sometimes useful for scripts. If you want the sort to respect locale, remove that.

The <() construct obtains the descriptor to read from the spawned pipeline, and < redirects the standard input of the while loop to it. If you need to access the standard input inside the pipe, you may use another descriptor — exercise for the reader :).

Now, back to the beginning. The read built-in reads output from the redirected stdin. Setting empty IFS disables word splitting which is unnecessary here — as a result, read reads the whole 'line' of input to the single provided variable. -r option disables escape processing that is undesired here as well. Finally, -d '' sets the line delimiter to NUL — that is, tells read to read zero-terminated strings.

As a result, the loop is executed once for every successive zero-terminated array element, with the value being stored in e. The example just puts the items in another array but you may prefer to process them directly :).

Of course, that's just one of the many ways of achieving the same goal. As I see it, it is simpler than implementing complete sorting algorithm in bash and in some cases it will be faster. It handles all special characters including newlines and should work on most of the common systems. Most importantly, it may teach you something new and awesome about bash :).

Answer 7

In the 3-hour train trip from Munich to Frankfurt (which I had trouble to reach because Oktoberfest starts tomorrow) I was thinking about my first post. Employing a global array is a much better idea for a general sort function. The following function handles arbitary strings (newlines, blanks etc.):

declare BSORT=()
function bubble_sort()
{   #
    # @param [ARGUMENTS]...
    #
    # Sort all positional arguments and store them in global array BSORT.
    # Without arguments sort this array. Return the number of iterations made.
    #
    # Bubble sorting lets the heaviest element sink to the bottom.
    #
    (($# > 0)) && BSORT=("$@")
    local j=0 ubound=$((${#BSORT[*]} - 1))
    while ((ubound > 0))
    do
        local i=0
        while ((i < ubound))
        do
            if [ "${BSORT[$i]}" \> "${BSORT[$((i + 1))]}" ]
            then
                local t="${BSORT[$i]}"
                BSORT[$i]="${BSORT[$((i + 1))]}"
                BSORT[$((i + 1))]="$t"
            fi
            ((++i))
        done
        ((++j))
        ((--ubound))
    done
    echo $j
}

bubble_sort a c b 'z y' 3 5
echo ${BSORT[@]}

This prints:

3 5 a b c z y

The same output is created from

BSORT=(a c b 'z y' 3 5) 
bubble_sort
echo ${BSORT[@]}

Note that probably Bash internally uses smart-pointers, so the swap-operation could be cheap (although I doubt it). However, bubble_sort demonstrates that more advanced functions like merge_sort are also in the reach of the shell language.

Answer 8

Keep it simple ;)

In the following example, the array b is the sorted version of the array a!

The second line echos each item of the array a, then pipes them to the sort command, and the output is used to initiate the array b.

a=(2 3 1)
b=( $( for x in ${a[@]}; do echo $x; done | sort ) )
echo ${b[@]} # output: 1 2 3

Answer 9

min sort:

#!/bin/bash
array=(.....)
index_of_element1=0

while (( ${index_of_element1} < ${#array[@]} )); do

    element_1="${array[${index_of_element1}]}"

    index_of_element2=$((index_of_element1 + 1))
    index_of_min=${index_of_element1}

    min_element="${element_1}"

        for element_2 in "${array[@]:$((index_of_element1 + 1))}"; do
            min_element="`printf "%s\n%s" "${min_element}" "${element_2}" | sort | head -n+1`"      
            if [[ "${min_element}" == "${element_2}" ]]; then
                index_of_min=${index_of_element2}
            fi
            let index_of_element2++
        done

        array[${index_of_element1}]="${min_element}"
        array[${index_of_min}]="${element_1}"

    let index_of_element1++
done

Answer 10

If you can compute a unique integer for each element in the array, like this:

tab='0123456789abcdefghijklmnopqrstuvwxyz'

# build the reversed ordinal map
for ((i = 0; i < ${#tab}; i++)); do
    declare -g ord_${tab:i:1}=$i
done

function sexy_int() {
    local sum=0
    local i ch ref
    for ((i = 0; i < ${#1}; i++)); do
        ch="${1:i:1}"
        ref="ord_$ch"
        (( sum += ${!ref} ))
    done
    return $sum
}

sexy_int hello
echo "hello -> $?"
sexy_int world
echo "world -> $?"

then, you can use these integers as array indexes, because Bash always use sparse array, so no need to worry about unused indexes:

array=(a c b f 3 5)
for el in "${array[@]}"; do
    sexy_int "$el"
    sorted[$?]="$el"
done

echo "${sorted[@]}"

• Pros. Fast.
• Cons. Duplicated elements are merged, and it can be impossible to map contents to 32-bit unique integers.

Answer 11

try this:

echo ${array[@]} | awk 'BEGIN{RS=" ";} {print $1}' | sort

Output will be:

3
5
a
b
c
f

Problem solved.

Answer 12

array=(a c b f 3 5)
new_array=($(echo "${array[@]}" | sed 's/ /\n/g' | sort))    
echo ${new_array[@]}

echo contents of new_array will be:

3 5 a b c f

Answer 13

There is a workaround for the usual problem of spaces and newlines:

Use a character that is not in the original array (like $'\1' or $'\4' or similar).

This function gets the job done:

# Sort an Array may have spaces or newlines with a workaround (wa=$'\4')
sortarray(){ local wa=$'\4' IFS=''
             if [[ $* =~ [$wa] ]]; then
                 echo "$0: error: array contains the workaround char" >&2
                 exit 1
             fi

             set -f; local IFS=$'\n' x nl=$'\n'
             set -- $(printf '%s\n' "${@//$nl/$wa}" | sort -n)
             for    x
             do     sorted+=("${x//$wa/$nl}")
             done
       }

This will sort the array:

$ array=( a b 'c d' $'e\nf' $'g\1h')
$ sortarray "${array[@]}"
$ printf '<%s>\n' "${sorted[@]}"
<a>
<b>
<c d>
<e
f>
<gh>

This will complain that the source array contains the workaround character:

$ array=( a b 'c d' $'e\nf' $'g\4h')
$ sortarray "${array[@]}"
./script: error: array contains the workaround char

description

• We set two local variables wa (workaround char) and a null IFS
• Then (with ifs null) we test that the whole array $*.
• Does not contain any woraround char [[ $* =~ [$wa] ]].
• If it does, raise a message and signal an error: exit 1
• Avoid filename expansions: set -f
• Set a new value of IFS (IFS=$'\n') a loop variable x and a newline var (nl=$'\n').
• We print all values of the arguments received (the input array $@).
• but we replace any new line by the workaround char "${@//$nl/$wa}".
• send those values to be sorted sort -n.
• and place back all the sorted values in the positional arguments set --.
• Then we assign each argument one by one (to preserve newlines).
• in a loop for x
• to a new array: sorted+=(…)
• inside quotes to preserve any existing newline.
• restoring the workaround to a newline "${x//$wa/$nl}".
• done

Answer 14

This question looks closely related. And BTW, here's a mergesort in Bash (without external processes):

mergesort() {
  local -n -r input_reference="$1"
  local -n output_reference="$2"
  local -r -i size="${#input_reference[@]}"
  local merge previous
  local -a -i runs indices
  local -i index previous_idx merged_idx \
           run_a_idx run_a_stop \
           run_b_idx run_b_stop

  output_reference=("${input_reference[@]}")
  if ((size == 0)); then return; fi

  previous="${output_reference[0]}"
  runs=(0)
  for ((index = 0;;)) do
    for ((++index;; ++index)); do
      if ((index >= size)); then break 2; fi
      if [[ "${output_reference[index]}" < "$previous" ]]; then break; fi
      previous="${output_reference[index]}"
    done
    previous="${output_reference[index]}"
    runs+=(index)
  done
  runs+=(size)

  while (("${#runs[@]}" > 2)); do
    indices=("${!runs[@]}")
    merge=("${output_reference[@]}")
    for ((index = 0; index < "${#indices[@]}" - 2; index += 2)); do
      merged_idx=runs[indices[index]]
      run_a_idx=merged_idx
      previous_idx=indices[$((index + 1))]
      run_a_stop=runs[previous_idx]
      run_b_idx=runs[previous_idx]
      run_b_stop=runs[indices[$((index + 2))]]
      unset runs[previous_idx]
      while ((run_a_idx < run_a_stop && run_b_idx < run_b_stop)); do
        if [[ "${merge[run_a_idx]}" < "${merge[run_b_idx]}" ]]; then
          output_reference[merged_idx++]="${merge[run_a_idx++]}"
        else
          output_reference[merged_idx++]="${merge[run_b_idx++]}"
        fi
      done
      while ((run_a_idx < run_a_stop)); do
        output_reference[merged_idx++]="${merge[run_a_idx++]}"
      done
      while ((run_b_idx < run_b_stop)); do
        output_reference[merged_idx++]="${merge[run_b_idx++]}"
      done
    done
  done
}

declare -ar input=({z..a}{z..a})
declare -a output

mergesort input output

echo "${input[@]}"
echo "${output[@]}"

Answer 15

Many thanks to the people that answered before me. Using their excellent input, bash documentation and ideas from other treads, this is what works perfectly for me without IFS change

array=("a \n c" b f "3 5")

Using process substitution and read array in bash > v4.4 WITH EOL character

readarray -t sorted < <(sort < <(printf '%s\n' "${array[@]}"))

Using process substitution and read array in bash > v4.4 WITH NULL character

readarray -td '' sorted < <(sort -z < <(printf '%s\0' "${array[@]}"))

Finally we verify with

printf "[%s]\n" "${sorted[@]}"

output is

[3 5]
[a \n c]
[b]
[f]

Please, let me know if that is a correct test for embedded /n as both solutions produce the same result, but the first one is not supposed to work properly with embedded /n

Answer 16

a=(e b 'c d')
shuf -e "${a[@]}" | sort >/tmp/f
mapfile -t g </tmp/f

Answer 17

I am not convinced that you'll need an external sorting program in Bash.

Here is my implementation for the simple bubble-sort algorithm.

function bubble_sort()
{   #
    # Sorts all positional arguments and echoes them back.
    #
    # Bubble sorting lets the heaviest (longest) element sink to the bottom.
    #
    local array=($@) max=$(($# - 1))
    while ((max > 0))
    do
        local i=0
        while ((i < max))
        do
            if [ ${array[$i]} \> ${array[$((i + 1))]} ]
            then
                local t=${array[$i]}
                array[$i]=${array[$((i + 1))]}
                array[$((i + 1))]=$t
            fi
            ((i += 1))
        done
        ((max -= 1))
    done
    echo ${array[@]}
}

array=(a c b f 3 5)
echo " input: ${array[@]}"
echo "output: $(bubble_sort ${array[@]})"

This shall print:

 input: a c b f 3 5
output: 3 5 a b c f

Answer 18

Great answers here. Learned a lot. After reading them all, I figure I'd throw my hat into the ring. I think this is the shortest method (and probably faster as it doesn't do much shell script parsing, though there is the matter of the spawning of printf and sort, but they're only called once each) and handles whitespace in the data:

a=(3 "2 a" 1)                                                # Setup!
IFS=$'\n' b=( $(printf "%s\n" "${a[@]}" | sort) ); unset IFS # Sort!
printf "'%s' " "${b[@]}";                                    # Success!

Outputs:

'1' '2 a' '3'

Note that the IFS change is limited in scope to the line it is on. if you know that the array has no whitespace in it, you don't need the IFS modification.

Inspiration was from @yas's answer and @Alcamtar comments.

EDIT

Oh, I somehow missed the actually accepted answer which is even shorter than mine. Doh!

IFS=$'\n' sorted=($(sort <<<"${array[*]}")); unset IFS

Turns out that the unset is required because this is a variable assignment that has no command.

I'd recommend going to that answer because it has some interesting stuff on globbing which could be relevant if the array has wildcards in it. It also has a detailed description as to what is happening.

EDIT 2

GNU has an extension in which sort delimits records using \0 which is good if you have LFs in your data. However, when it gets returned to the shell to be assign to an array, I don't see a good way convert it so that the shell will delimit on \0, because even setting IFS=$'\0', the shell doesn't like it and doesn't properly break it up.

Answer 19

array=(z 'b c'); { set "${array[@]}"; printf '%s\n' "$@"; } \
    | sort \
    | mapfile -t array; declare -p array
declare -a array=([0]="b c" [1]="z")

• Open an inline function {...} to get a fresh set of positional arguments (e.g. $1, $2, etc).
• Copy the array to the positional arguments. (e.g. set "${array[@]}" will copy the nth array argument to the nth positional argument. Note the quotes preserve whitespace that may be contained in an array element).
• Print each positional argument (e.g. printf '%s\n' "$@" will print each positional argument on its own line. Again, note the quotes preserve whitespace that may be contained in each positional argument).
• Then sort does its thing.
• Read the stream into an array with mapfile (e.g. mapfile -t array reads each line into the variable array and the -t ignores the \n in each line).
• Dump the array to show its been sorted.

As a function:

set +m
shopt -s lastpipe

sort_array() { 
    declare -n ref=$1
    set "${ref[@]}"
    printf '%s\n' "$@"
    | sort \
    | mapfile -t $ref
}

then

array=(z y x); sort_array array; declare -p array
declare -a array=([0]="x" [1]="y" [2]="z")

I look forward to being ripped apart by all the UNIX gurus! :)

Answer 20

sorted=($(echo ${array[@]} | tr " " "\n" | sort))

In the spirit of bash / linux, I would pipe the best command-line tool for each step. sort does the main job but needs input separated by newline instead of space, so the very simple pipeline above simply does:

Echo array content --> replace space by newline --> sort

$() is to echo the result

($()) is to put the "echoed result" in an array

Note: as @sorontar mentioned in a comment to a different question:

The sorted=($(...)) part is using the "split and glob" operator. You should turn glob off: set -f or set -o noglob or shopt -op noglob or an element of the array like * will be expanded to a list of files.