How can I edit this code so it compiles on ISO C90 and not just ISO C99?

Asked Nov 16 '22 at 21:45

Active Nov 16 '22 at 22:41

Viewed 27 times

I'm currently running a shell project, I tried to compile the code using: `

gcc -Wall -Werror -Wextra -pedantic -std=gnu89 *.c -o hsh

The compilation method is mandatory for my project. The code compiles on ISO C99 (-std=gnu99), but returned the error: ISO C90 forbids variable length array when I used the above compilation method. How can I edit this code instead so it compiles on ISO C90?

This is the code I tried:

int i = 0, j = 0, k = 1;
int n = find_chars_number(s, sep, idx) + 1;
int array[n];
int o = 0;

array[0] = idx;

Error found on the line int array[n]; nb: find_chars_number is a function I invoked

edited Nov 16 '22 at 22:41

John Bollinger

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asked Nov 16 '22 at 21:45

Jasper

You need to use dynamic memory allocation for the array, e.g. `int *array = malloc(n * sizeof(int));` Or you have to declare an array that's big enough for the worst case. – user3386109 Nov 16 '22 at 21:48
1

possible answer on [this question](https://stackoverflow.com/questions/10234288/iso-c90-forbids-variable-length-array) – emetsipe Nov 16 '22 at 21:49
If you decide to use `malloc`, be sure to `free` the memory when you're done with it. – user3386109 Nov 16 '22 at 21:56
Pre-C99, it was common to use `alloca` for this sort of thing. – Steve Summit Nov 16 '22 at 23:20

How can I edit this code so it compiles on ISO C90 and not just ISO C99?

0 Answers0