uint32_t number = 00000000000000000000000000001011;
std::cout << number;
Why is the number's value 521 here?
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Peter Mortensen
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Gevv
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6because `0` at the beginning means octal, 1011 in octal is 521 in decimal – Iłya Bursov Nov 19 '22 at 16:13
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2You may be interested in the `0b` prefix – harold Nov 19 '22 at 16:14
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Number literals starting with a zero are interpreted as octal numbers (base 8). 1011 in base 8 is 521.
maja
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Yes, sort of; constants that begin with "0x" are hexadecimal, and constants that begin with "0b" are binary; if there's only a 0 followed by more octal digits it is, indeed, octal. – Pete Becker Nov 19 '22 at 18:08
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