Kotlin Regex to Extract after and before a specific character

Question

In Kotlin, i need to find the string value after and before of specific character,

For example,

Item1. myResultValue: someother string

So in the above, I need to get the value after ". " and before ":" SO my output should be "myResultValue". If it doesn't match it can return empty or null value.

Please help to write to Regex for this.

Does this answer your question? [Regular Expression to find a string included between two characters while EXCLUDING the delimiters](https://stackoverflow.com/questions/1454913/regular-expression-to-find-a-string-included-between-two-characters-while-exclud) — aSemy, Nov 24 '22 at 05:24
Can there be multiple such patterns in the string i.e. multiple `. ` or `:`? What output do you expect in that case? Just the first match or all of them? — Arpit Shukla, Nov 24 '22 at 06:53

score 1 · Answer 1 · answered Nov 24 '22 at 08:17

For your specific case you can use regex:

val text = "Item1. myResultValue: someother string"

val pattern = Pattern.compile(".*\\.(.*):.*")
val matcher = pattern.matcher(text)
if (matcher.matches()) {
    println(matcher.group(1))
}

If you want to build something smarter that defines the start and end pattern you can do it like this:

val startSearch = "\\."
val endSearch = ":"
val text = "Item1. myResultValue: someother string"

val pattern = Pattern.compile(".*$startSearch(.*)$endSearch.*")
val matcher = pattern.matcher(text)
if (matcher.matches()) {
    println(matcher.group(1))
}

Kotlin Regex to Extract after and before a specific character

1 Answers1