Multiplication gives wrong output in java

Question

Code

    public class main {
    
        public static void main(String[] args) {
            System.out.println(1101101101*10);
        }
    
    }

OUTPUT

-1873890878

I do the same thing in python it gives the output.

     Microsoft Windows [Version 10.0.19044.2251]
    (c) Microsoft Corporation. All rights reserved.

    C:\Users\pradeep>python
    Python 3.10.8 (tags/v3.10.8:aaaf517, Oct 11 2022, 16:50:30) [MSC v.1933 64 bit (AMD64)] on win32
    Type "help", "copyright", "credits" or "license" for more information.
    >>> 1101101101*10
    11011011010

How can I solve this in java ?

You've encountered *integer overflow*, the topic of numerous questions and answers on this site, and covered in a myriad of textbooks and websites. Let your search engine be your friend. — High Performance Mark, Nov 24 '22 at 06:47
`Math.multiplyExact( 1101101101 , 10 )` throws an exception if you overflow. — Basil Bourque, Nov 24 '22 at 07:25

score 2 · Answer 1 · answered Nov 24 '22 at 06:56

Any number written literally like 1101101101 or 10 is considered an Integer by default in java. And Integer in java represents any whole number from -2147483648 to 2147483647. your argument makes the output exceed the said range, your IDE probably raise a warning that said Numeric overflow in expression, maybe you didn't notice that.

score 1 · Answer 2 · answered Nov 24 '22 at 06:52

1

Below code might solve your problem .

 public static void main(String[] args) {

    Long longVal = 1101101101l;
    System.out.println(longVal*10);
}

answered Nov 24 '22 at 06:52

Abirami Balasubramaniyan

51
4

Multiplication gives wrong output in java

2 Answers2