I just compiled Ruby from source and it is located into /usr/local/ruby
In order to access Ruby's executables I edited ~/.zshenv
adding /usr/local/ruby/bin
to the export PATH
directive:
export PATH=/usr/local/ruby/bin:/usr/local/mysql/bin:/usr/local/sbin:/usr/local/bin:$PATH
^^^^^^^^^^^^^^^^^^^^
However restarting the terminal and running which ruby
still returns macOS's default /usr/bin/ruby
In fact inspecting PATH
reveals:
% echo $PATH
/usr/local/bin:/usr/bin:/bin:/usr/sbin:/sbin:/Library/Apple/usr/bin:/usr/local/ruby/bin:/usr/local/mysql/bin:/usr/local/sbin:
So after my ~/.zshenv
is excecuted another configuration file prepends /usr/bin
to PATH
.
Where does this happen?
I would expect to find /usr/bin
already in PATH
when .zshenv
is processed (resulting in having this path at the end of the environment variable).
What I am missing?
I checked and there are no other zsh configuration files in my home directory, just .zshenv
;
I checked /etc
too and found
zprofile
zshrc
zshrc_Apple_Terminal
but none of those do alter the PATH
variable
on /etc/paths
I have
/usr/local/bin
/usr/bin
/bin
/usr/sbin
/sbin
but again, shouldn't be PATH
already set with those paths when .zshenv
is processed ?