Python: How to convert Timestamp which of precision 9 to datetime object?

Question

I am fetching crypto data from the ByBit exchange which is returning the timestamp field created_at_e9 in the following format: 1663315207126761200

The standard is 11 -13 digits but here are 20 digits. How do I fetch the DateTime from it?

Does this answer your question? [Converting unix timestamp string to readable date](https://stackoverflow.com/questions/3682748/converting-unix-timestamp-string-to-readable-date) (just adjust the unit) — FObersteiner, Nov 28 '22 at 15:48

ShadowCrafter_01 · Accepted Answer · 2022-11-28T16:07:57.227

1

You can look at this so see how to convert a timestamp into a datetime in python. And since the timestamp presision is 1e9 you can simply multiply the value by 1e-9 or divide it by 1e9 to get the timestamp in seconds.

from datetime import datetime
datetime.fromtimestamp(created_at_e9 * 1e-9)

edited Nov 28 '22 at 16:07

answered Nov 28 '22 at 15:44

ShadowCrafter_01

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You should add some explanation about your code, e.g. the exact problem and what you fix – Giacomo Catenazzi Nov 28 '22 at 16:03

Python: How to convert Timestamp which of precision 9 to datetime object?

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