How to round number to 3 decimals max?

Question

I am trying to round up 5.9999998 to 5.999.

But I have a problem, If I do round(number) it'll round it up to 6. How can I round a number like this to max 3 decimals?

Read (study) both answers: https://stackoverflow.com/questions/13479163/round-float-to-x-decimals — PM 77-1, Dec 01 '22 at 19:14
Does this answer your question? [Round float to x decimals?](https://stackoverflow.com/questions/13479163/round-float-to-x-decimals) — President James K. Polk, Dec 01 '22 at 19:35
Are you trying to _round_, _round up_ or _truncate_? You mention all three options and it is not clear what you're asking. Please [edit] your question to clarify what you mean, and use the correct words (round/ceil/floor/truncate) to make this question searchable and useful for future readers. — wovano, Dec 28 '22 at 16:36
Note that due to ambiguity of the question, there are now different answers with different results... — wovano, Dec 28 '22 at 16:38

score 3 · Answer 1 · answered Dec 01 '22 at 19:18

3

You can use this:

number = 5.999999998
new_number = int(number * 1e3) / 1e3

answered Dec 01 '22 at 19:18

3dSpatialUser

score 0 · Answer 2 · answered Dec 01 '22 at 19:21

0

Here is a short code.


x = 4/3

# round up to 3 decimal places
x = round(x, 3)

print(x)

answered Dec 01 '22 at 19:21

Dhruvin Vadgama

2

This is not quite what he wants, he doesn't want to round , but to truncate I think he is confusing the two terms – MathAng Dec 01 '22 at 19:23
Do you mean not round off the last digit but taking only the 3 digits after the decimal point? – Dhruvin Vadgama Dec 01 '22 at 19:26
Nope, that's what I meant. Thanks, it works. – er21r21 Dec 01 '22 at 19:31
3

Really ? When you execute this code with your number : 5.9999998 it returns 6.0, not 5.999, then I think your example was wrong – MathAng Dec 01 '22 at 19:37

2 Answers2