String array in C prints whole array instead of value at pointer

Asked Dec 04 '22 at 15:22

Active Dec 04 '22 at 15:22

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As the title suggests i'm trying to read a value stored in an array of strings in C, but whenever i print that value, it will print every other value after that.

if(len == 2){
      if(instruction[0] >> 4 == 6){
        char sixes[][4] = {"addl", "subl", "andl", "xorl"};
        int x = instruction[0] & 0xf;
        printf("%s\n", sixes[x]);
        continue;
      }

considering this is identical to what tutorials say to do im at a loss

the expected outcome would be addl andl subl xorl

what i keep getting is addlsublandlxorl andlxorl sublandlxorl xorl

ive checked that the pointer is correct and it is, im so confused

asked Dec 04 '22 at 15:22

Noseph

4

The sub-arrays for the strings in `sixes` are to small. A four-character string needs space for *five* characters to fit the null-terminator. – Some programmer dude Dec 04 '22 at 15:25

String array in C prints whole array instead of value at pointer

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