I have a part of code where I need to multiply number from 0-9 and print it out, but I do it by taking one integer at a time and multiplying it by 4 this time, but I don't know what to do when after multiplying I get two digit number. I can only print the mod of it. please help!!!!
Someone said to go to the end of a buffer but I also don't know how to do that...
work:
MOV dl, [si]
sub dl,48
mov bl,dl
mov al,4 ; this can be changed from 0-9
mul bl
mov ah,2
mov dl,al
count:
cmp dl,09H ;compares with 9
jbe moveon
ja ifmorethanten
ifmorethanten:
mov ax,dx
mov bl, 10
div bl ;al=ax/bl ah=ax%bl
mov dl, al
cmp dl, 09H
jbe moveon
ja ifmorethanten
add dl,48
push ax
mov ah,02h
int 21h
pop ax
mov dl, ah
moveon:
MOV [di], dl
INC si ;moving on to another buffer's integer
INC di ;ignore it I put the number into another buffer here
LOOP work
Maybe I should do it somehow different please help me!!!
