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how do i run a .exe file by writing a line in powershell if my .exe file is located in "C:\Program Files\Rainmeter" and the name of the file is Rainmeter.exe ?

im just trying to make a script sry if this question is dumb

i have already tried these lines

 C:
13:18:42 ❯ cd C:\Program Files\Rainmeter>.\Rainmeter.exe Set-Location: A positional parameter cannot be found that accepts argument 'Files\Rainmeter>.\Rainmeter.exe'.

 C:
13:18:58 ❯ cd C:\Program Files\Rainmeter.\Rainmeter.exe Set-Location: A positional parameter cannot be found that accepts argument 'Files\Rainmeter.\Rainmeter.exe'.

 C:
13:19:14 ❯ cd C:\Program Files\Rainmeter.\Rainmeter.exe Set-Location: A positional parameter cannot be found that accepts argument 'Files\Rainmeter.\Rainmeter.exe'.

 C:
13:04:43 ❯ c:\Program Files\Rainmeter>.\Rainmeter.exe c:\Program: The term 'c:\Program' is not recognized as a name of a cmdlet, function, script file, or executable program. Check the spelling of the name, or if a path was included, verify that the path is correct and try again.

 C:
13:07:09 ❯ cd C:\Program Files\Rainmeter\Rainmeter.exe Set-Location: A positional parameter cannot be found that accepts argument 'Files\Rainmeter\Rainmeter.exe'.

1 Answers1

0

The solution to your question can be found in this thread: Executing an EXE file using a PowerShell script

Example code:

& "c:\temp\foo.exe"