Slipt in python superfluous one character " "

Question

I'm newer to Python and When I use .slipt() superfluous one character

txt = "8/"

x = txt.split("/")

print(x)

result is:

['8', '']

but I want the result is:

['8']

how to fix it

Answer 1

You are getting this because .slipt() Method split a string into a list. Using /, as a separator, split a string into a list with the respect to "/". In the asked question:

txt = "8/"

x = txt.split("/")

print(x)

You are split the string with respect to "/". You can visualize txt = "8/" as txt = "8"+"/"+"". If you want your output to do this ['8']. You can use x.remove("") to remove "" so the Final Code is:

txt = "8"+"/"+""

x = txt.split("/")
x.remove("")

print(x)

Answer 2

Just use list slicing:

x = txt.split("/")[0]

Prints:

8

But convert it to a list again:

x = list(txt.split("/")[0])

Prints:

['8']

Since your list contains two values, use indexing - [0] to get the first at the zeroth index.

See also

Understanding slicing

Answer 3

x = list(txt.split("/")[0])

or

x = list(txt.split("/")[-2])

Slicing

Answer 4

You can use strip and then split. Strip remove the character in front or back to avoid empty strings

Code:

txt = "8/"
x = txt.strip("/").split("/")
print(x)

It also works if there is leading / in the string.

Code:

txt = "/8/"
x = txt.strip("/").split("/")
print(x)

Output:

['8']

Answer 5

text = "8/"

#Create a list of words from the text
words = text.split("/")

# Remove any empty elements from the list
filtered_list = [word for word in words if word.strip()]

print(filtered_list)

Output: ['8']