Finding the actuall index of an repeated element in a list

Question

I am trying to find the capital letters in a word and append their indexes in new list

eg:

Input           Output
pYtHoN          [1, 3, 5]
CApiTAls    [0, 1, 4, 5]

I created new list containing all the letters and checked if they are capital or not and append the result in a new list:

word = input()
word_list = list(word)

upper_case_list = []
for letter in word_list:
    if letter == letter.upper():
        upper_case_list.append(word_list.index(letter))

print(upper_case_list)

But my output is:

CApiTAls
[0, 1, 4, 1]

My output gives me the index 1 instead index 5:

['C', 'A', 'p', 'i', 'T', 'A', 'l', 's']

How can I get the actual index of A at index 5 and not repeated index 1?

Note: Im self-teaching to programming, also new.

Why use `.index` to find the index of the character? You're iterating over the string, you already know the index. Use `enumerate` — Pranav Hosangadi, Jan 01 '23 at 17:46
Alternatively, see https://stackoverflow.com/questions/5419204/index-of-duplicates-items-in-a-python-list — Pranav Hosangadi, Jan 01 '23 at 17:47
Note also that you don't need to turn `word` into a list - you can already iterate over a string — ndc85430, Jan 01 '23 at 17:52

score 2 · Answer 1 · answered Jan 01 '23 at 17:49

Use enumerate to access the index while iterating. (list.index will only return the first index of an element.)

for index, letter in enumerate(word_list):
    if letter.isupper():
        upper_case_list.append(index)

Or, with a list comprehension:

upper_case_list = [index for index, letter in enumerate(word_list) if letter.isupper()]

Finding the actuall index of an repeated element in a list

1 Answers1