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The string value

value = "[new=user,pass=h[]@,repalce=que]"

I need the output to be as a list

list = [ "new=user","pass=h[]@","repalce=que" ]

  

I am new to python just want to know how to deal with these type convertions
Pavan Sai
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7 Answers7

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You can use the split method as follows:

value = "[new=user,pass=h[]@,repalce=que]"

splitList = value.split(",")

print(splitList)

The split method takes the character that you want to split the sentence on as a parameter.

Anonymous
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You can do that in this particular case by the following command

value_list = value[1:-1].split(',')

This way you will first get rid of the brackets (first and last character) and then split by the comma. I do not think there is a more elegant way since this is a rather rare case. I would recommend loading lists as lists or other variables in their correct format and avoid changing the type.

Daniel Bl
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  • Thankyou! it worked, but what if value has an extra ',' ? like value = "[new=user,pass=h[],@,repalce=que]" – Pavan Sai Jan 02 '23 at 14:57
  • Then there is nothing you can really do but manually make sure you avoid these cases or when saving the file using a different way to separate the items, like with a semi-colon: "[new=user;pass=h[],@;repalce=que]" – Daniel Bl Jan 03 '23 at 17:50
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you can use str.split

value = "[new=user,pass=h[]@,repalce=que]"
result = value.split(',')

please note that list is a type. I recommend not to use it as a variable name.

Mr. Nun.
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  • Thankyou! it worked, but what if value has an extra ',' ? like value = "[new=user,pass=h[],@,repalce=que]" – Pavan Sai Jan 02 '23 at 14:52
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You could do it using a list comprehension like this:

value = "[new=user,pass=h[]@,repalce=que]"

new_value = [t.replace('pass', 'test') for t in value[1:-1].split(',')]

print(new_value)

Output:

['new=user', 'test=h[]@', 'repalce=que']

Note:

This only works for this particular case.

Also, there's no "type conversion" here

DarkKnight
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Clean the string thyen convert string to list by string.split()

value = "[new=user,pass=h[]@,repalce=que]"
value = value [1:-1].split(",")
print(value)

output #

['new=user', 'pass=h[]@', 'repalce=que']
Bhargav - Retarded Skills
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  • Thankyou! it worked, but what if value has an extra ',' ? like value = "[new=user,pass=h[],@,repalce=que]" – Pavan Sai Jan 02 '23 at 14:54
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I assume the []@ is not supposed to be taken as list. So this is my solution, maybe it would be better to use regex but whatever.

value = "[new=user,pass=h[]@,repalce=que]"
def func(x):
    n=len(x)
    x=list(x)
    s=e=-1
    for i in range(0,n-2,1):
        if x[i]=='[' and x[i+1]!=']' and x[i+2]!='@':s=i
        if x[i]==']' and x[i-1]!='[' and x[i+1]!='@':e=i
    x[s]=x[e]=''
    x=''.join(x)
    x=x.split(',')
    return x
print(func(value))
Donald Duck
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Vishnu Balaji
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You could split the string

# Python code to convert string to list
  
def Convert(string):
    li = list(string.split(" "))
    return li
 
str1 = "Item1 Item2 Item3"
print(Convert(str1))

Output:

['Item1', 'Item2', 'Item3']
HoneyBearTech
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