How to convert string to list inside of list?

Question

I don't know how to convert string to list inside of list. Split method seems the most popular, but it doesn't work.

I have a list:

corpus = ['[(0, 1), (1, 2), (2, 1)]']

I want to convert string to list like that:

corpus = [[(0, 1), (1, 2), (2, 1)]]

How I can do it?

Does this answer your question? [python string list to list ast.listeral\_eval](https://stackoverflow.com/questions/10113270/python-string-list-to-list-ast-listeral-eval) — Chandler Bong, Jan 06 '23 at 14:36
What is *slit method*? What makes you say it "doesn't work"? — Scott Hunter, Jan 06 '23 at 14:37

score 3 · Accepted Answer · answered Jan 06 '23 at 14:38

3

Use ast.literal_eval, a safer alternative to eval:

import ast
corpus = ['[(0, 1), (1, 2), (2, 1)]']
corpus = [ast.literal_eval(item) for item in corpus]
print(corpus)
# [[(0, 1), (1, 2), (2, 1)]]

answered Jan 06 '23 at 14:38

Timur Shtatland

12,024
2
30
47

score 0 · Answer 2 · answered Jan 06 '23 at 15:01

Hi I think this simple code will help.

import re

corpus = ['[(0, 1), (1, 2), (2, 1)]']
corpus[0] = re.findall(r'\(\d, \d\)', corpus[0])
temp_lst1 = []

for i in corpus[0]:
    temp_lst2 = []
    for j in i:
        try:
            if type(int(j)) == int:
                temp_lst2.append(int(j))
        except ValueError:
            pass
    temp_lst1.append(tuple(temp_lst2))

corpus[0] = temp_lst1

print(corpus)

How to convert string to list inside of list?

2 Answers2